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kozerog [31]
3 years ago
7

What type of motion does this graph represent?

Physics
1 answer:
Fantom [35]3 years ago
5 0
An object moving with constant velocity
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Standards for all managers ethical responsibilities are covered in a company's?
katen-ka-za [31]

Answer:

C. Code of ethics

Explanation:

The code of ethics of a company is the document where all the values that the members of the company should live and obbey, they are often guideliness on how to act and beheave and how to treat customers, providers and co-workers. IT also has all of the standards for all managers ethical responsabilities, and ethical responsabilities of the general of the employees of the company.

5 0
3 years ago
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Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t
Nezavi [6.7K]

Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

calculation of RT equivalent resistance

is:  

RT = R1 + R2 + R3

We replace the data of the statement in the previous expression and it remains:  

5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

5 0
2 years ago
Find the momentum of a train with a mass of 850 kg and forward velocity of 15 m/s
LenKa [72]

Answer:

12,750

Explanation:

P = mv

Momentum = Mass x Velocity

Plug it in and finish equation

7 0
3 years ago
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The 1.0-kg collar slides freely on the fixed circular rod. Calculate the velocity v of the collar as it hits the stop at B if it
soldi70 [24.7K]

Answer:

6.21 m/s

Explanation:

Using work energy equation then

U_{1-2}=T_B- T_A\\58d-mgh=0.5m(v_b^{2}-v_a^{2})

where d is displacement from initial to final position, v is velocity and subscripts a and b are position A and B respectively, m is mass of collar, g is acceleration due to gravity

Substituting 1 Kg for m, 0.4m for h, v_a as 0, 9.81 for g then

58(\sqrt{0.4^{2}+0.3^{2}}-0.1)-(1\times 9.81\times 0.4)=0.5\times 1\times (v_b^{2}-v_a^{2})\\19.276=0.5\times 1v_b^{2}\\v_b=6.209025688 m/s\approx 6.21 m/s

7 0
3 years ago
The mass of a mass-and-spring system is displaced 10 cm from its equilibrium position and released. A frequency of 4.0 Hz is obs
scoundrel [369]

Answer:

It will remain same i.e. 4.0 Hz

Explanation:

In a mass-and-spring system, the frequency depends upon the mass (m) and the spring constant (k).

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

Since, the frequency does not depend on the initial displacement of the mass, the frequency would remain the same i.e. 4.0 Hz.

7 0
3 years ago
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