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Alekssandra [29.7K]
4 years ago
7

According to the concept of length contraction, what happens to the length of an object as it approaches the speed of light and

then slows down, eventually coming to a stop? It is always observed as contracting. It is always observed as the same length. It is observed as expanding and then contracting back to its original length. It is observed as contracting and then expanding back to its original length.
Physics
1 answer:
lord [1]4 years ago
8 0
When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.
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If a 0.5 kg pair of running shoes would weigh 11.55 Newton’s on Jupiter, what is the strength of gravity there?
OverLord2011 [107]
The weight of an object is given by
F=mg
where m is the mass of the object, while g is the strength of the gravity (which corresponds to the gravitational acceleration of the planet).

In our problem, the shoes have a mass of m=0.5 kg, and their weight is F=11.55 N. So, we can re-arrange the previous formula to find the value of g:
g= \frac{F}{m}= \frac{11.55 N}{0.5 kg}=23.1 N kg^{-1}
and this is the strength of the gravity on Jupiter's surface.

4 0
3 years ago
Write a small paragraph on how to determine the speed of sound using the time of flight method.
Makovka662 [10]

Answer:

time of flight of a pulse, and these most often

involve triggering of the measuring oscilloscope

with the signal that generates the sound pulse and

timing the time delay of the pulse picked up by a

conveniently placed microphone4­5

. Loren Winters

has reported a method similar in principle to the

present one, but which uses a completely different

detection system6

.

Explanation:

6 0
3 years ago
Use the information from the graph to answer the question. What is the acceleration of the object
Art [367]

Answer:

-2.5 m/s²

Explanation:

The acceleration of a body is the change in it's velocity with time.

The change in velocity with time can be obtained as the slope of a velocity time graph ;

Acceleration = (change in velocity / change in time)

Taking the slope :

Change in Velocity = △y = y2 - y1

Change in time = △x = x2 - x1

(10, 15) ; (0, 40)

△y / △x = y2 - y1 / x2 - x1 = (40 - 15) / (0 - 10)

△y / △x = 25 / - 10 = - 2.5 m/s²

4 0
3 years ago
How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius
maria [59]

Answer:

897

Explanation:

Speed of the car, v = 126 km/h, converting to m/s, we have v = 35 m/s and

Radius of the curve, R = 150 mm = 0.15 m

The centripetal acceleration a(c) is given by the formula = v² / R so that

a(c) = 35² / 0.15

a(c) = 1225 / 0.15

a(c) = 8167 m/s²

The force that causes the acceleration is frictional force = µ m g, where

µ = coefficient of friction

m = the mass of the car and

g = acceleration due to gravity, 9.81

From Newton's law:

µ m g = m a(c) , so that

µ = a(c) / g

µ = 8167 / 9.81

µ = 897

Therefore, the coefficient of static friction must be as big as 897

5 0
3 years ago
An object is moving at a velocity of 23 m/s. It accelerates to a stop over a time of 8.3 s.
Lady bird [3.3K]
Very good question, The answer you might be looking for is 7.467m/s^2.

Have a blessed day God bless.
3 0
3 years ago
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