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alex41 [277]
3 years ago
11

Two children of mass 27 kg and 51 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c

hildren are separated by a distance of 4 m, at what distance from the pivot point is the small child sitting in order to maintain the balance?
Physics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

2.62 m

Explanation:

Let the small child sit at a distance x from the pivot.

The distance of big child from the pivot is 4 - x .

By using the concept of moments.

Clockwise moments = anticlockwise moments

27 x = 51 ( 4 - x )

27 x = 204 - 51 x

78 x = 204

x = 2.62 m

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To find the final velocity of the object which accelerates at 40m/s/s for four minutes, we first need to convert the 4 minutes to seconds. There are 60 seconds in a minute so 4 minutes is equal to 4x60 = 240 seconds.

To calculate the final velocity we just multiply the acceleration rate by the time, so 40x240=9,600 m/s

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