Answer:
a)
a = 1/5
b = 1/3
b)
x(1/3) = 2.500
y(1/3) = 2.598
c)
x'(t) = -5π sin(π t)
d)
x'(1/3) = -13.603
Explanation:
Hi!
a)
We can notice that
x(t)/5 = cos(πt)
y(t)/3 = sin(πt)
Therefore:
( x(t) / 5 )^2 + ( y(t) / 3 )^2 = cos^2(πt) + sin^2(πt) = 1
That is:
a = 1/5
b = 1/3
b)
At t=1/3
x(1/3) = 5 cos(π/3)
y(1/3) = 3 sin(π/3)
But
cos(π/3) = 1/2 = 0.5
sin(π/3) = √3 / 2 = 0.866
That is:
x(1/3) = 2.5
y(1/3) = 2.598
c)
The horizontal velocity is:
x'(t) = -5π sin(π t)
d)
at time t =1/3
x'(1/3) = -5π sin(π/3) = -13.603
Answer:
8.6 m/s
Explanation:
The components of the initial velocity of the ball can be found by using the equations:
where
is the horizontal component
is the vertical component
v is the magnitude of the velocity
is the angle above the horizontal
Substituting:
v = 15 m/s
We find:
Answer:
I would agree with the statement. it's not just the body, but everything that we see is almost 99.9999% empty space
Answer:
They measured their train using their handspan
