All categories

3 years ago

Which of the following are equivalent units?

Physics

2 answers:

bezimeni [28]3 years ago

4 0

Answer: B) a newton-meter and a joule

Explanation:

Joule is the unit if energy. One joule is equal to one Newton-meter.

1 J = 1 N-m

Energy is equivalent to work done which is equal to dot product of force and displacement.

E = W = F.s

Energy is measured in Joules. Force is measured in Newtons and displacement is measured in meters.

1 Joule = 1 kg m²/s²

1 N = 1 kg m/s²

1 N-m = 1 kg m/s² × m = 1 kg m²/s² = 1 J

asambeis [7]3 years ago

3 0

Answer : The correct options are, (B) a newton-meter and a joule and (C) a newton and a joule/sec

Explanation :

As we know that,

$1N=1Kg\text{ m }s^{-2}\\\\1J=1\text{Kg }m^2s^{-2}\\\\1W=1\text{Kg }m^2s^{-3}$

or we can say that,

$1W=1J/s\\\\1J=1Nm\\\\1N=1J/s\\\\1W=1Nms^{-1}$

From the given options, the option B and C are the equivalent units.

Hence, the correct options are, (B) and (C)

You might be interested in

The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb

Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 $in^{2}$

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = $\frac{F}{A}$

⇒ P = $\frac{6.4}{0.4}$

⇒ P = 16 $\frac{lb}{in^{2} }$

This is the pressure inside the cylinder.

Let force applied on the brake pad = $F_{1}$

Area of the brake pad ( $A_{1}$ )= 1.7 $in^{2}$

Thus the pressure on the brake pad ( $P_{1}$ ) = $\frac{F_{1} }{A_{1} }$

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = $P_{1}$

⇒ 16 = $\frac{F_{1} }{A_{1} }$

⇒ $F_{1}$ = 16 × $A_{1}$

Put the value of $A_{1}$ we get

⇒ $F_{1}$ = 16 × 1.7

⇒ $F_{1}$ = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = $\frac{F_{1} }{4}$ = $\frac{27.2}{4}$ = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0

3 years ago

Select the correct answer.

motikmotik

I'm not sure. But it can be A or C.

4 0

3 years ago

Please answer this question

sergij07 [2.7K]

Explanation:

m = kg. v=m/s. g=m/s^2. h= m

>>1/2mv^2=mgh

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m

>>1/2mv^2=mgh>> kg*(m/s)^2= kg*m/s^2*m>>kg m^2/s^2=kg m^2/s^2 the fraction 1/2 won't be able to make any changes to to the dimensional expression of energy i.e half of energy is still energy therefore you can neglect the number .

>>kg m^2/s^2=kg m^2/s^2 

>>J= J

3 0

3 years ago

The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed under the 40 cm mark and car

Nitella [24]

Answer:

W = 30 N

Explanation:

Applying the summation of torques about the wedge for equilibrium, taking the clockwise direction as negative. Since the ruler is balanced horizontally about the wedge. Therefore, the summation of all torques acting about the wedge must be equal to zero.

$(70\ N)(40\ cm - 10\ cm)-(30\ N)(50\ cm-40\ cm)-(W)(100\ cm - 40\ cm) = 0\\W(60\ cm) = (70\ N)(30\ cm)-(30\ N)(10\ cm)\\\\W = \frac{1800\ N.cm}{60\ cm}$

W = 30 N

6 0

2 years ago

The graph below shows the relationship between speed and time for two objects, A and B. Compare with the acceleration of object

Licemer1 [7]

Sorry I can’t give the answer cause I don’t have the graph
I’m so sorry but if u give the graph I will be able to give the answer

7 0

3 years ago