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mixas84 [53]
2 years ago
7

Two boys are at the top of a waterslide at Seven Peaks Water Park. One boy (boy A) slips off the top of the tower and falls unob

structed into the pool below. At the same moment the other boy (boy B) starts sliding down the slide and lands in the same pool. Ignoring air resistance and friction, which boy will splash into the water first and which will have the greater speed when he hits the water?
Physics
1 answer:
Illusion [34]2 years ago
4 0

Answer: boy B, same

Explanation:

Given

One boy trips off the waterslide while the other starts sliding down

As there is no horizontal velocity, both boys have to travel the same vertical distance.

Their starting vertical velocity is zero and they need to travel the same vertical distance. Therefore, both boys splash water with the same velocity.

The time taken by boy B is more than boy A as boy B will travel some horizontal distance due to slide which will increase its time to reach the bottom.

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HELP PLEASE BOYLES LAW
kogti [31]

Answer:

3 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

0.75 × 2 = 0.5 × V₂

1.5 = 0.5 × V₂

Divide both side by 0.5

V₂ = 1.5 / 0.5

V₂ = 3 L

Thus, the new volume of the Ne gas is 3 L

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3 years ago
I need help with question #8 please!!
otez555 [7]

Answer: 3.1158

Explanation: THERE

3 0
2 years ago
According to Boyle’s Law, increasing the pressure of a gas will have which effect on its volume?
Alisiya [41]
The volume will decrease

7 0
3 years ago
Help me please, need more assistance
Dmitrij [34]

Explanation:

12) q = mCΔT

125,600 J = (500 g) (4.184 J/g/K) (T − 22°C)

T = 82.0°C

13) Solving for ΔT:

ΔT = q / (mC)

a) ΔT = 1 kJ / (0.4 kg × 0.45 kJ/kg/K) = 5.56°C

b) ΔT = 2 kJ / (0.4 kg × 0.45 kJ/kg/K) = 11.1°C

c) ΔT = 2 kJ / (0.8 kg × 0.45 kJ/kg/K) = 5.56°C

d) ΔT = 1 kJ / (0.4 kg × 0.90 kJ/kg/K) = 2.78°C

e) ΔT = 2 kJ / (0.4 kg × 0.90 kJ/kg/K) = 5.56°C

f) ΔT = 2 kJ / (0.8 kg × 0.90 kJ/kg/K) = 2.78°C

14) q = mCΔT

q = (2000 mL × 1 g/mL) (4.184 J/g/K) (80°C − 20°C)

q = 502,000 J

20) q = mCΔT

q = (2000 g) (4.184 J/g/K) (100°C − 15°C) + (400 g) (0.9 J/g/K) (100°C − 15°C)

q = 742,000 J

24) q = mCΔT

q = (0.10 g) (0.14 J/g/K) (8.5°C − 15°C)

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6 0
3 years ago
These are nontoxic, nonflammable chemicals containing atoms of carbon, chlorine, and fluorine that have created a hole in the oz
Grace [21]
<span>The correct answer is: Chlorofluorocarbons (CFCs)

Explanation:
In simple words, CFCs are the chemical compounds made up of the following three elements:
1. Carbon
2. Chlorine
3. Fluorine

When CFCs compounds reach the upper atmosphere, the ultraviolet rays coming from the Sun break those compounds into individual elements, which then react with one of the oxygen atom of the ozone (O3) to form new compounds like chlorine monoxides. That way the ozone molecules get destroyed, resulting into the ozone depletion. Hence, the correct answer is Chlorofluorocarbons (CFCs).</span>
6 0
3 years ago
Read 2 more answers
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