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iragen [17]
3 years ago
15

25 POINTS PLEASE HELP I BEG YOU!!

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0

Answer:

13\frac{1}{3}

13 slices with \frac{1}{3} of left over.

Step-by-step explanation:

To solve this problem we just need to divide, you can deduct that from Sasha's intention, she wants to cut, that's division. So, the bread is 10-inch, and she wanna have slices of 3/4 inch. In other words, we must divide 10 by 3/4, that's the cut Sasha wants to make:

10\div\frac{3}{4}=10\frac{4}{3}=\frac{40}{3}=13.333333

This result means that she will have 13 slices of 3/4 inches, and 0.3333333 would be left over, which is 1/3.

Therefore, the result would be 13\frac{1}{3}, as a mixed number.

Nezavi [6.7K]3 years ago
3 0

Answer:

13 slices, 3/10 inches left.

Step-by-step explanation:

10 divided by 3/4 = 10 divided by .75

10 divided by .75 = 13.3

13 slices, .3 inches (3/10) leftover

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3 years ago
compute the mean and variance of the following discrete probability distribution. (round your answers to 2 decimal places.) x p(
a_sh-v [17]

The  determined value of mean µ is 1.3 and variance σ² is 0.81.

What is mean and variance?

  • A measurement of central dispersion is the mean and variance. The average of a group of numbers is known as the mean.
  • The variance is calculated as the square root of the variance.
  • We can determine how the data we are collecting for observation are dispersed and distributed by looking at central dispersion.

The table is attached as an image for reference.

Mean µ = ∑X P(X)

         µ = 1.3

Variance (σ² ) = ∑ X² P(X)- (µ)²

                       = 2.5-(1.3)²

                (σ² ) = 0.81

The  determined value of mean µ is 1.3 and variance σ² is 0.81.

Learn more about mean and variance here:

brainly.com/question/25639778

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6 0
2 years ago
A city planner designs a park that is a quadrilateral with vertices at J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1). There is an e
Vadim26 [7]

use the eqn below to find the mid-pts

x-mid-pt = (x₁+x₂)/2

y-mid-pt = (y₁+y₂)/2

J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1)

So

midpoint JK = (-1+1/2, 1+3/2) = (0,2)

midpoint KL = (1+5/2, 3+⁻1/2) = (3,1)

midpoint LM = (5+⁻3/2, ⁻1+⁻1/2) = (1,-1)

midpoint MJ = (⁻3+⁻1/2, -1+1/2) = (-2,0)


use the eqn to find distance:


d = √(x₂ - x₁)² + (y₂ - y₁)²


Distance between JK and LM = √(0⁻1)² + (2 - ⁻1)² = √1 + 9 = √10

Distance between JM and KL = √(3-⁻2)² + (1-0)² = √25 + 1 = √26

Scale is 10

Actual distance = 10*(√10 + √26) = 82.6 = 83 units


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3 years ago
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The answer is 43 when you add 29 back to 57 then divide by 2
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