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Lostsunrise [7]
2 years ago
12

A high ph value indicates:

Chemistry
1 answer:
mote1985 [20]2 years ago
8 0
... indicates that it also has a high concentration of Hydroxide (OH) and that it is more basic.
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A chemist performs the following reaction:
tester [92]

Answer:

9.17 g

Explanation:

1) Calculate mols of PCl5

PCl5 (aq) + 4H2O (l) ⟶ H3PO4 (aq) + 5HCl (aq)

Mass of PCl5: 26.5g

Molar Mass of PCl5 208.24g/mol

Mol of PCl5 = Mass PCl5 /Molar mass PCl5  = 26.5g / (208.24g/mol) = 0.127257011 mol

2) Calculate mols of water needed to react

Mols of H2O per 1 Mols of PCl5 = 4 (because 4 water is needed to Phosphorus pentachloride).

Mols of H2O = Mol of PCl5 * 4 = 0.127257011 * 4 = 0.509028044 mols

3) Calculate Grams of water needed to react

Mols of H2O = 0.509028044 mols

Molar Mass of H2O = 18.015 g/mol

Mass of H2O = Mols of H2O * Molar Mass of H2O

= 0.509028044 mols* 18.015 g/mol = 9.17014021 g

sf = 3

9.17 g

4 0
2 years ago
Which of the following statements is true about the role of oxygen in cellular respiration? It reacts with water. It is one of t
skad [1K]

"It reacts with water" is incorrect I took the test and got it wrong. I believe it is B, because oxygen combines with glucose and makes carbon dioxide.

6 0
3 years ago
Read 2 more answers
1. The heating system that uses the energy<br> of the sun to produce heat is a
user100 [1]

Answer:

solar heating system

Explanation:

6 0
3 years ago
What’s the answer to this?
MArishka [77]

Benzene

  • Benzene has low density than the water itself of about 0.9 g/cm³

Low denisty object than the water usually <u>floats on the water</u>.

Another example: orange peel which floats on water has density of about 0.84 g/cm³

8 0
1 year ago
0.22 L of HNO3 is titrated to equivalence using 0.18 L of 0.2 MNaOH. What is the concentration of the HNO3?
andre [41]

Answer:

0.16 M

Explanation:

Data provided as per the question is below:-

Volume of HNO_3 = 0.22 L

The Volume of NaOH = 0.18 L

Morality of NaOH = 0.2

According to the given situation, the calculation of the concentration of the HNO_3 is shown below:-

For equivalence,

Number of the equivalent of HNO_3 = Number of equivalents of NaOH

= \frac{0.18\times0.2}{0.22}

= \frac{0.036}{0.22}

= 0.16363 M

or

= 0.16 M

7 0
2 years ago
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