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3 years ago

Which of the following represents the greatest number of atoms?

1 answer:

7 0

The correct option is B. To get the number of atom for each compound, each element in the compound will be counted as an atom. For instance, for Fe[ClO4]2, there are 1 atom of Fe, 2 atoms of Cl, and 8 atoms of O, making a total of 11 atoms [1 + 2 + 8= 11]. The other options have less than 11 atoms.

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What would the temperature of 0.734 moles of chlorine gas be at 1.83 atmospheres in a 10.2

lesya [120]

Answer: 310K

Explanation:

Given that:

Volume of Chlorine gas V = 10.2L

Temperature T = ?

Pressure P = 1.83 atm

Number of moles of chlorine gas N = 0.734 moles

Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.83atm x 10.2L= 0.734 moles x 0.0821 atm L K-1 mol-1 x T

18.67atm L = 0.0603 atm L K-1 x T

T = (18.67atm L / 0.0603 atm L K-1)

T = 309.8K (Round up to 310K)

Thus, the temperature of the chlorine gas is 310 kelvin

5 0

4 years ago

Sound molecules can "stack up" in front of airplanes traveling at very high

Eduardwww [97]

D. Sonic booms. Hope this helps

7 0

4 years ago

If the oxidation state of H is +1 and O is -2, what is the oxidation state of C in C2H4O?

Sedbober [7]

Answer:

-1

Explanation:

According to this question, the oxidation state/number of H and O in C2H4O is +1 and -2 respectively.

The oxidation state of carbon in the compound can be calculated thus:

Where;

x represents the oxidation number of C

C2H4O = 0 (net charge)

x(2) + 1(4) - 2 = 0

2x + 4 - 2 = 0

2x + 2 = 0

2x = -2

Divide both sides by 2

x = -1

The oxidation number of C in C2H4O is -1.

8 0

3 years ago

Calculate the moles of 25.2 g Na2S2O8

vekshin1

Answer:

To calculate the moles we must first find the molar mass M

M (Na2S2O8) = (23*2) + (32*2) + (16*8)

= 46 + 64 + 168

= 278g/mol

Molar mass = mass/moles

moles =mass / molar mass

= 25.2/278

= 0.0906mol

Hope this helps.

4 0

4 years ago

Se realiza una mezcla de minerales de Cu y Fe: 20 kg FeS2 (pirita), 70 kg de Fe2O3 (hemetita) 15 kg de CuFe2 (calcopirita) y 90

Artemon [7]

Answer:

34.78% Fe

39.66% Cu

5.48% S

20.07% O

Explanation:

Para resolver esta pregunta debemos hallar la masa de cada átomo en cada mineral. Así, podremos hallar el porcentaje de cada átomo:

Pirita (Fe: 55.845g/mol; S: 32.065g/mol; FeS2: 119.975g/mol)

Masa Fe:

20kg FeS2 * (1*55.845g/mol / 119.975g/mol) = 9.31kg Fe

Masa S:

20kg FeS2 * (2*32.065g/mol / 119.975g/mol) = 10.69kg S

Hemetita (Fe: 55.845g/mol; O: 16g/mol; Fe2O3: 159.688g/mol)

Masa Fe:

70kg Fe2O3 * (2*55.845g/mol / 159.688g/mol) = 48.96kg Fe

Masa O:

70kg Fe2O3 * (3*16g/mol / 159.688g/mol) = 21.04kg O

Calcopirita (Fe: 55.845g/mol; Cu: 63.546g/mol; CuFe2: 175.236 g/mol)

Masa Fe:

15kg CuFe2 * (2*55.845g/mol / 175.236 g/mol) = 9.56kg Fe

Masa Cu:

15kg CuFe2 * (1*63.546g/mol / 175.236 g/mol) = 5.44kg Cu

Tenorita (O: 16g/mol; Cu: 63.546g/mol; CuO: 79.545 g/mol)

Masa O:

90kg CuO * (1*16g/mol / 79.545 g/mol) = 18.10kg O

Masa Cu:

90kg CuO * (1*63.546g/mol / 79.545 g/mol) = 71.90kg Cu

Masa Total: 20kg + 70kg + 15kg + 90kg = 195kg

Porcentaje Hierro:

9.31kg Fe + 48.96kg Fe + 9.56kg Fe / 195kg * 100 =

34.78% Fe

Porcentaje Cobre:

5.44kg Cu + 71.90kg Cu / 195kg * 100 =

39.66% Cu

Porcentaje Azufre:

10.69kg S / 195kg * 100 =

5.48% S

Porcentaje Oxígeno:

21.04kg O + 18.10kg O/ 195kg * 100 =

20.07% O

8 0

3 years ago