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IrinaVladis [17]
3 years ago
13

Sodium metal (Na) reacts explosively with water to form sodium hydroxide (NaOH) and hydrogen gas. How many moles of sodium are n

eeded to produce 154 moles of hydrogen gas? (Hint: Balance the equation.)
Chemistry
1 answer:
Sati [7]3 years ago
7 0

Answer:

308 moles of sodium

Explanation:

The balanced equation for the chemical reaction between sodium metal (Na) and water (H₂O) is the following:

2 Na(s) + 2 H₂O → 2 NaOH(aq) + H₂(g)

From the equation, we can see that 2 moles of Na react with 2 moles of H₂O to give 2 moles of NaOH and 1 mol of H₂ (hydrogen gas). So the stoichiometric mole ratio between Na and H₂ is: 2 mol Na/1 mol H₂. Thus, we multiply the mole ratio by the moles of H₂ to be produced to obtain the moles of Na required:

moles of Na required =  2 mol Na/1 mol H₂ x 154 moles H₂ = 308 moles Na

Therefore, 308 moles of sodium are needed to produce 154 moles of hydrogen gas.

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What happens when you react ascorbic<br> acid(vitamin c) with iodine.
Stella [2.4K]

Answer:

When ascorbic acid reacts with iodine then acid reacts to oxidize which means loose electron while iodine reacts to reduce which means gain electron.

Explanation:

We know that ascorbic acid which consists of vitamin C is very crucial for the growth of teeth, bone, etc. It also helps in regulating the chemical reaction of cells in the body.

When ascorbic acid reacts with iodine then acid reacts to oxidize which means loose electron while iodine reacts to reduce which means gain electron.

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How do Hydrogen-1, Hydrogen-2, and Hydrogen-3 differ from each other?
Anna71 [15]

Answer:

different from the number of their neutrons

Explanation:

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7 0
3 years ago
Calculate the mass in grams for 2.28 moles of N2?
alexandr402 [8]
I think it’s 63.84 or 64
3 0
3 years ago
A geological sample is found to have a Pb-206/U-238 mass ratio of 0.337/1.00. Assuming there was no Pb-206 present when the samp
nikdorinn [45]

Answer:

2.1x10⁹ years

Explanation:

U-238 is a radioactive substance, which decays in radioactive particles. It means that this substance will lose mass, and will form another compound, the Pb-206.

The time need for a compound loses half of its mass is called half-life, and knowing the initial mass (mi) and the final mass (m) the number of half-lives passed (n) can be found by:

m = mi/2ⁿ

The mass of Pb-206 will be the mass that was lost by U-238, so it will be mi - m. Thus, the mass ration can be expressed as:

(mi-m)/m = 0.337/1

mi - m = 0.337m

mi = 1.337m

Substituing mi in the expression of half-life:

m = 1.337m/2ⁿ

2ⁿ = 1.337m/m

2ⁿ = 1.337

ln(2ⁿ) = ln(1.337)

n*ln(2) = ln(1.337)

n = ln(1.337)/ln2

n = 0.4190

The time passed (t), or the age of the sample, is the half-life time multiplied by n:

t = 4.5x10⁹ * 0.4190

t = 1.88x10⁹ ≅ 2.1x10⁹ years

5 0
3 years ago
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