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aleksandr82 [10.1K]
3 years ago
12

A 38.4−g sample of ethylene glycol, a car radiator coolant, loses 852 J of heat. What was the initial temperature of the ethylen

e glycol if the final temperature is 32.5°C? (c of ethylene glycol = 2.42 J/g·K)
Chemistry
1 answer:
irina [24]3 years ago
4 0

Answer:

296.33K

Explanation:

Data;

Q = 852J

mass (m) = 38.4g

θ₂ = 32.5°C = 305.5K

θ₁ = ?

c = 2.42 J/g.K

From the equation of heat transfer;

Heat transfer (Q) = MC∇θ

Q = mc(θ₂ - θ₁)

852 = 38.4 * 2.42 * ( 305.5 - θ₁ )

852 = 28389.504 - 92.928θ₁

Collect like-terms

92.928θ₁ = 27537.504

Divide both sides by 92.928 to make θ₁ the subject of formula .

θ₁ = 296.33K

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2.0 L of Carbon dioxide is heated from -25.0 °C to Standard Temperature.
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The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

  • V1 = 2L
  • V2 = ?
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  • T2 = 273K

2/248 = V2/273

273 × 2 = 248V2

546 = 248V2

V2 = 546/248

V2 = 2.2L

Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L

Learn more about volume at: brainly.com/question/11464844

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2 years ago
9. Diamonds and quartz crystals look very similar but diamonds cost considerably
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A chocolate bar weighs 4.00 ounces. If the chocolate delivers 2.78 calories per gram, how many
dimulka [17.4K]

Answer:

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Explanation:

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if you have 4 ounces then it would be equal to about 113.4 grams. then you would divide that by 2.78 which will equal about 40.8

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