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Answer:
vf = 3.27[m/s]
Explanation:
In order to solve this problem we must analyze each body individually and find the respective equations. The free body diagram of each body (box and bucket) should be made, in the attached image we can see the free body diagrams and the respective equations.
With the first free body diagram, we determine that the tension T should be equal to the product of the mass of the box by the acceleration of this.
With the second free body diagram we determine another equation that relates the tension to the acceleration of the bucket and the mass of the bucket.
Then we equalize the two stress equations and we can clear the acceleration.
a = 3.58 [m/s^2]
As we know that the bucket descends 1.5 [m], this same distance is traveled by the box, as they are connected by the same rope.
And the speed can be calculated as follows:
Answer:
Amplitude is the vertical distance between a ridge and the midpoint of the wave.
Explanation:
A mechanical wave is a disturbance that travels through a material or substance that is a medium of the wave. For example, when a tense string is pressed, the disturbance caused spreads along it in the form of a wave pulse. The disturbance in this case consists in the variation of The Shape of the string from its equilibrium state
it is important to know:
Crest: the crest is the highest point of this amplitude.
Period: the period is the time it takes the wave to go from one point of maximum amplitude to the next.
Amplitude: amplitude is the vertical distance between a crest and the midpoint of the wave.
Frequency: number of times that vibration is repeated.
Valley: it is the lowest point of a wave.
Wavelength: distance between two consecutive ridges of this size.
Transverse wave velocity.-
The propagation speed of a wave on a string (v) is proportional to the square root of the string tension (T) and inversely proportional to the square root of the linear density (μ) of the string: