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victus00 [196]
4 years ago
8

which has a higher acceleration:a 10kg object acted upon with a net force of 20N or an 18kg object acted on by a net force of 20

N
Physics
2 answers:
MA_775_DIABLO [31]4 years ago
7 0
<span>Answer: The acceleration of 10 kg object is greater than that of 18 kg object.

Explanation:
According to Newton's Second law:
F = ma --- (A)

Let's find the acceleration for both 10 kg and 18 kg objects!
The net force on both of these masses = F = 20N

(1) Acceleration of 10 kg object
Mass = m = 10 kg
Plug in the values in equation (A):
20 = 10 * a
Acceleration = a = 2 m/s^2

(2) Acceleration of 18 kg object
Mass = m = 18 kg
Plug in the values in equation (A):

20 = 18 * a
Acceleration = a = 1.11 m/s^2


2 > 1.11; therefore, 10 kg object has the higher acceleration compared to the acceleration of the 18 kg object.</span>
Juliette [100K]4 years ago
6 0

Explanation:

The expression of the applied force in terms of mass and acceleration by using Newton's second law is as follows;

F= ma

Here, m is the mass of the object and a is the acceleration of the object.

Calculate the acceleration of a 10 kg object acted upon with net force of 20 N in the above expression.

Put m= 10 kg and F= 20 N in the above expression.

20= (10)a

a= 2 m/s^2

Calculate the acceleration of a 18 kg object acted upon with net force of 20 N in the above expression.

Put m= 18 kg and F= 20 N.

20= (18)a

a= 1.11 m/s^2

Therefore, the acceleration of a 10 kg object acted upon with net force of 20 N is greater than the acceleration of a 18 kg object acted upon with net force of 20 N.

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Basile [38]

Answer:

U_f = (U_o)/2)

Explanation:

The capacitance of a given capacitor is given by the formula;

C = ε_o•A/d

While energy stored in plates capacitor is given as; U_o = Q²/2C

Now,we are told that that all the dimensions of the capacitor plate is doubled. Thus, we now have;

C' = ε_o•4A/2d

Hence, C' = 2C

so capacitance is now doubled

Thus, the final energy stored between the plates of capacitor is given as;

U_f = Q²/2C'

From earlier, we saw that C' = 2C.

Thus;

U_f = Q²/2(2C)

U_f = Q²/4C

Rearranging, we have;

U_f = (1/2)(Q²/2C)

From earlier, U_o = Q²/2C

Hence,

U_f = (1/2)(U_o)

Or

U_f = (U_o/2)

4 0
3 years ago
Which of these activities performed by a chemist is primarily based on an understanding of physics?
Yanka [14]
Predicting the volume of a gas, given its temperature and pressure p<span>roperties.</span>
4 0
3 years ago
Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point,F⃗ 1F→1F_1_vec has a magnitude of 8.80 NN and is directed at an an
castortr0y [4]

Answer:

  • Fx = -9.15 N
  • Fy = 1.72 N
  • F∠γ ≈ 9.31∠-10.6°

Explanation:

You apparently want the sum of forces ...

  F = 8.80∠-56° +7.00∠52.8°

Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

  f∠α = (-f·cos(α), -f·sin(α))

This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.

  = -8.80(cos(-56°), sin(-56°)) -7.00(cos(52.8°), sin(52.8°))

  ≈ (-4.92090, 7.29553) +(-4.23219, -5.57571)

  ≈ (-9.15309, 1.71982)

The resultant component forces are ...

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  • Fy = 1.72 N

Then the magnitude and direction of the resultant are

  F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)

  F∠γ ≈ 9.31∠-10.6°

4 0
3 years ago
A boy pushes a 50 kg wheelbarrow with a velocity of 0.5 m/s. If he uses a force of 10 N, how far does he push
labwork [276]

Answer:

d=1.25 m

Explanation:

fd=.5mv2-.5mv1; 10(d)=.5(50)(.5)-0; 10(d)=12.5; d=12.5/10; d=1.25 m

4 0
3 years ago
Energy is transferred through a solid
Alex Ar [27]

Answer:

Conduction is the transfer of thermal energy through direct contact between particles of a substance, without moving the particles to a new location. Usually occurs in solids. When heat is supplied to one end, molecules at that end start to move more quickly.

Explanation:

5 0
3 years ago
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