The value of the angle of the incline

at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:

where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction

and the normal reaction of the incline N.
The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:

Therefore, the initial equation becomes

From which we find


For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.
Telescope magnifies light coming from distant objects.
Part A)
Distance is given as sum of total path length
So here as we are given that car drives 40 miles East and 30 miles West
So here the total path length is


Part B)
Displacement is given as straight line distance between initial and final position
So here we can see that
East
West
Now the total displacement will be

<u><em>so the displacement will be 10 miles East</em></u>
An object moving in a circular path has centripetal acceleration. <em>(A)</em>
Answer:
4.14 cm.
Explanation:
Given,
For Coil 1
radius of coil, r₁ = 5.6 cm
Magnetic field, B₁ = 0.24 T
For Coil 2
radius of coil, r₂ = ?
Magnetic field, B₂ = 0.44 T
Using formula of maximum torque

Since both the coil experience same maximum torques
now,





Radius of the coil 2 is equal to 4.14 cm.