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zmey [24]
3 years ago
8

In normal conditions, warm water "piles up" in the Western Pacific Ocean. True False

Chemistry
1 answer:
kakasveta [241]3 years ago
8 0
In normal conditions, warm water does "pile up" in the" Western Pacific Ocean.
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NaOH+H3PO4=Na3PO4+H20
statuscvo [17]
Wait is that suppose to be a question??!!
4 0
3 years ago
Iodine would have chemical properties most like?
mrs_skeptik [129]
<span>manganese (Mn)
.tellurium (Te)
.chlorine (Cl).
<span>xenon (Xe).</span></span>
6 0
3 years ago
Given that Kp [NOTE: Kp!!!!] = 1.39 at 400 ºC for the reaction, P4(g) &lt;=&gt; 2 P2(g), which answer best describes the reactio
Igoryamba

Answer:

The reaction will proceed to the left to attain equilibrium.

Explanation:

The question is missing but I guess it must be about <em>how the reaction will proceed to attain equilibrium.</em>

First, we have to calculate the partial pressures using the ideal gas equation.

pP_{4}=\frac{2.50mol\times (0.08206atm.L/mol.K)\times 673K}{25.0L} =5.52atm

pP_{2}=\frac{1.50mol\times (0.08206atm.L/mol.K)\times 673K}{25.0L}=3.31atm

Now, we have to calculate the reaction quotient (Qp).

Qp=\frac{pP_{2}^{2}}{pP_{4}} =\frac{3.31^{2} }{5.52} =1.98

Since Qp > Kp, the reaction will proceed to the left to attain equilibrium.

3 0
3 years ago
Inorganic chemicals: Select one:
natka813 [3]

Answer:

E

Explanation:

Inorganic chemicals are present both in ground and surface water. Inorganic chemicals are found in soil from which they may contaminate runoff and eventual find their way into surface water bodies. Also, inorganic ions may be leached into underground aquifers and contaminate or underground water .

5 0
3 years ago
PLEASE HELP ASAP!!!!
Vsevolod [243]

Answer:

The answer to your question is  C = 0.037 cal/g°C

Explanation:

Data

mass of the wire = m = 237 g

temperature 1 = T1 = 25°C

temperature 2 = T2 = 107°C

Heat = Q = 722 cal

Specific heat = C

Process

1.- Write the formula to find the specific heat

            Q = mC(T2 - T1)

-Solve for C

            C = Q / m(T2 - T1)

2.- Substitution

             C = 722 / 237(107 - 25)

3.- Simplification

              C = 722 / 237(82)

              C = 722 / 19434

4.- Result

               C = 0.037 cal/g°C

4 0
3 years ago
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