$sin (30^{0})=\frac{c}{2}\Rightarrow \frac{1}{2}=\frac{c}{2}\Rightarrow 2*\frac{1}{2}=2*\frac{c}{2}\Rightarrow c=1\\sin(60^0)=\frac{b}{2}\Rightarrow \frac{\sqrt{3}}{2}=\frac{b}{2}\Rightarrow b=\sqrt{3}\Rightarrow\: b\approx \:1.73$

Once one leg is found there is another way to find the other leg, using Pythagorean Theorem too.

$a^{2}=b^{2}+c^{2}\Rightarrow 2^{2}=b^{2}+1^{2}\Rightarrow 4-1=b^{2}\Rightarrow b=\sqrt{3} b\approx 1.73$

Sides

a hypotenuse: 2.00

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b leg: 1.73

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c leg: 1.00

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4 0

3 years ago

stilt scored 5 points less than twice the number scored by dunk. together they scored 43 points. how many points were scored by

gizmo_the_mogwai [7]

Set up a system of equations:

s = 2d - 5
s + d = 43

Where 's' represents the number of points Stilt scored and 'd' represents the number of points Dunk scored.

Plug in 2d - 5 for 's' in the 2nd equation:

s + d = 43

2d - 5 + d = 43

Combine like terms:

3d - 5 = 43

Add 5 to both sides:

3d = 48

Divide 3 to both sides:

d = 16

Plug this back into any of the two equations to find 's':

s + d = 43

s + 16 = 43

Subtract 16 to both sides:

s = 27

So Dunk scored 16 points and Stilt scored 27 points.

4 0

2 years ago