Answer:
Its passive
Explanation:
Facilitated diffusion is a type of passive transport that allows substances to cross membranes with the assistance of special transport proteins.
Answer:
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Explanation:
Step 1: Data given
Nitric acid = HNO3
Molar mass of H = 1.01 g/mol
Molar mass of N = 14.0 g/mol
Molar mass O = 16.0 g/mol
Number of moles nitric acid (HNO3) = 0.25 moles
Molairty = 0.10 M
Step 2: Calculate molar mass of nitric acid
Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)
Molar mass HNO3 = 1.01 + 14.0 + 3*16.0
Molar mass HNO3 = 63.01 g/mol
Step 3: Calculate mass of solute use
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 0.25 moles * 63.01 g/mol
Mass HNO3 = 15.75 grams
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Answer:
B and C
Explanation:
I think the answer correct is C because you never know in what temperature the block of ice is going to melt but if it says select all that apply its possible that B might be useful.
Answer:
Aluminium (aluminum in American and Canadian English) is a chemical element with the symbol Al and atomic number 13. It is a silvery-white, soft, non-magnetic and ductile metal in the boron group. ... Aluminium is remarkable for its low density and its ability to resist corrosion through the phenomenon of passivation.
Explanation:
i did aluminum chemistry
Neutralization reaction takes place between an acid and a base to form salt and water.
In the given reaction the acid is hydrochloric acid HCl and the base is aluminum hydroxide (Al(OH)
).
The correct balanced equation for the neutralization reaction that occurs between aluminum hydroxide and hydrochloric acid can be represented as:

Al(OH)
can give 3 hydroxide,
ions which can neutralize the 3
ion produced by 3 HCl molecules giving 3 mole of water and the salt aluminum chloride, AlCl
.
Therefore the correct option will be.
D. Al(OH)3 + 3 HCl (aq) --> AlCl3(aq) + 3 H2O(l)