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adoni [48]
3 years ago
7

Refer to the example about diatomic gases A and B in the text to do problems 19 - 27. How many grams in 3 moles of A2?

Chemistry
2 answers:
dedylja [7]3 years ago
7 0

B.) 3

hope you have a okay day

(GAME OF THRONES RULES

Elenna [48]3 years ago
5 0

Answer:

3

Explanation:

thank you

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A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm
Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 ^{\circ}C or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55^{\circ}C = 328 K

Initial pressure = P = 845 mmHg

Assuming final  to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg  

The final temperature is obtained by following relation at constant volume

\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}

The final temperature is 407.57 K

7 0
3 years ago
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6 0
3 years ago
Read 2 more answers
an underground explosion generates sound waves that travel through solid rock, then through a lake and then air. describe how th
DIA [1.3K]

Answer: sound can slow down, so when it travels through all of that it's muffled and kind of blocked. sound travels at 332 metres per second so it's hard to stop the sound

Explanation:

7 0
3 years ago
How many moles are in 272 grams of hydrogen peroxide (H2O2) ?
Strike441 [17]

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll <em>use the molar mass of hydrogen peroxide</em> (H₂O₂), as follows:

  • 272 g ÷ 34 g/mol = 8 mol

There are 8 moles in 272 grams of hydrogen peroxide.

7 0
3 years ago
The concentration of sugar in a soft drink is measured to be 10.5%. how many grams of sugar are in 125 g of the drink?
viva [34]
The grams  of the sugar in 125 g of the drink is calculated as below

%M/m) = mass of the solute (sugar)/  mass of the  solvent(drink) x100

let the mass  of the solute(sugar) be represented by y

convert % into fraction by dividing by 100 = 10.5/100

10.5/100 = y/125

by cross multiplication

100y =1312.5
divide both side by 100

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5 0
4 years ago
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