Which of these 2A elements has the largest atomic radius?

in their mechanism of action, a difference between lipid-soluble and water-soluble hormones is that _____.

LenKa [72]

In their mechanism of action, a difference between lipid-soluble and water-soluble hormones is that lipid-soluble hormones diffuse into the cell's plasma membrane to access protein receptors, while water-soluble hormones bind to protein receptors on the plasma membrane without diffusion.

Examples of lipid-soluble hormones are steroids. Examples of water-soluble hormones are polypeptides.

4 0

4 years ago

In chemical reactions, what does the principle of conservation of mass mean?

Scilla [17]

I think It means that any balanced equation is conserved. Meaning that the equation is equal. The law states matter can’t be created or destroyed. In chemical reactions the mass of an element is the same before and after the product. There’s two sides two an equation the reactants side and the product’s side. Hope this helps.

3 0

3 years ago

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6 NaOH + 2 Al --> 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?

tatyana61 [14]

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of $Na_3AlO_3$ .

So, 1 mole of Al produce 1 mole of $Na_3AlO_3$ . .....statement 1)

Number of moles of Al in 258 gram of Al.

$n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles$

Therefore, from statement 1) number of moles of $Na_3AlO_3$ produced is also 9.556 moles.

7 0

3 years ago

Ammonia (NH3) is one of the most common chemicals produced in the united states. it is used to make fertilizer and other product

Greeley [361]

Answer:

a) N2 is the limiting reactant

b) 1215.9 grams NH3

c) 2283.6 grams H2

Explanation:

Step 1: Data given

Mass of N2 = 1000 grams

Molar mass N2 = 28 g/mol

Mass of H2 = 2500 grams

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) +3H2(g) → 2NH3(g)

Step 3: Calculate moles N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 1000 grams / 28.0 g/mol

Moles N2 = 35.7 moles

Step 4: Calculate moles H2

Moles H2 = 2500 grams / 2.02 g/mol

Moles H2 = 1237.6 moles

Step 5: Calculate limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. There will be consumed 35.7 moles.

H2 is in excess. There will react 3*35.7 = 107.1 moles

There will remain 1237.6 - 107.1= 1130.5 moles H2

This is 1130.5 * 2.2 = 2283.6 grams H2

Step 6: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 35.7 moles N2 we'll have 2*35.7 = 71.4 moles NH3

Step 7: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 71.4 moles * 17.03 g/mol

Mass NH3 = 1215.9 grams NH3

7 0

3 years ago

Carbon-14 naturally decay to carbon-_____. 13 12 10 15

lorasvet [3.4K]

Answer:

13 would be correct

Explanation:

4 0

3 years ago

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