Which of these 2A elements has the largest atomic radius?

The water cycle would not be possible without ______ and ________.

ipn [44]

Answer:

I think it's 4

Explanation:

but I don't really remember the water cycle

4 0

3 years ago

A mountaineer shouts for help Half a second later (0.5 she hears the echo How far away is the rock face which is reflecting her

Tema [17]

Answer:

82.5 metres

Explanation:

speed=330m|s

initial time taken =0.5÷2=0.25

distance=speed×time

330m|s × 0.25s = 82.5m

6 0

3 years ago

Choose the correct answer to complete the paragraph about the acceptance of the heliocentric model. In the second century BCE, t

PtichkaEL [24]

Answer:epicycles,copermicus, earth

Explanation:

4 0

3 years ago

Read 2 more answers

How many grams of aluminum sulfate: Al2(SO4)3 , would be formed if 250 g of H2SO4 react with aluminum? The reaction is: 2Al + 3H

NikAS [45]

Answer:

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

Explanation:

Step 1: Data given

Mass of H2SO4 = 250 grams

Molar mass H2SO4 = 98.08 g/mol

Step 2: The balanced equation

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

Step 3: Calculate moles H2SO4

Moles H2SO4 = mass H2SO4 / molar mass H2SO4

Moles H2SO4 = 250 grams / 98.08 g/mol

Moles H2SO5 = 2.55 moles

Step 4: Calculate moles Al2(SO4)3

For 2 moles Al we need 3 moles H2SO4 to produce 1 mol Al2(SO4)3 and 3 moles H2

For 2.55 moles H2SO4 we'll have 2.55/3 = 0.85 moles Al2(SO4)3

Step 5: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass

Mass Al2(SO4)3 = 0.85 moles * 342.15 g/mol

Mass Al2(SO4)3 = 290.8 grams

290.8 grams of aluminium sulfate (Al2(SO4)3) will be produced.

7 0

4 years ago

Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an

rosijanka [135]

Answer:

Mole fraction of hexane in your sample is 0,746

Explanation:

Based on the information you can write the following equations:

X + Y = 1 (1)

Where X is mole fraction of hecane and Y is mole fraction of toluene

Also, based on the assumption that the refractive index of the hexane + toluene mixture varies linearly with mole fraction you can write:

1,375X + 1497Y = 1406 (2)

Replacing (1) in (2):

1,375X + 1,497(1-X) = 1,406

1,375X - 1,497X + 1,497 = 1,406

-0,122X = -0,091

X = -0,091/-0,122

X = 0,746

Thus, the mole fraction of hexane in your sample is 0,746

Also you can know the mole fraction of toluene replacing this value in (1):

0,746 - Y = 1

Y = 1-0,746

Y = 0,254

I hope it helps!

4 0

3 years ago