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ohaa [14]
3 years ago
7

When a piano tuner strikes both the A on the piano and a 440 Hz tuning fork, he hears a beat every 2 seconds. The frequency of t

he piano's A is
Physics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

The  frequency is  f = 439.5 \  Hz        

Explanation:

From the question we are told that

   The frequency of the  tuning fork is  f_t  =  440 \ Hz

   The beat period is  T  =  2 \  s

Generally the beat frequency is mathematically represented as

       f_b  =  \frac{1}{T}

       f_b  =  \frac{1}{2}

      f_b  = 0.5 \  Hz

The  beat frequency is also represented mathematically as

     f_b  =  f_t  -  f

Where  f is the frequency of the piano

 So

       f =  440 -  0.5  

       f = 439.5 \  Hz        

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<u>Given:</u>

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The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

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3 years ago
Find the resistance of a stereo: current is 7 A voltage is 49 V.
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Answer:

R = 7 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance. In this way, we have the following equation.

V = I*R

where:

V = voltage = 49 [V] (units of volts)

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R = resistance [ohms]

Now clearing R.

R =V/I

R = 49/7

R = 7 [amp]

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3 years ago
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