Index Contours are indicated by a thicker line compared to the others. Index Contours are labelled with specific elevations along it to give a better understanding of the scale of elevation.
The elevations on the Index Contour along with the legend of the map, that allows you read intermediate contour lines, gives you a clear perspective of increasing/decreasing elevation.
Answer:
True
Explanation:
This is because to know how someone behaves, they have to perform a particular action.
Answer:
The work and heat transfer for this process is = 270.588 kJ
Explanation:
Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k
The Pressure-Volume relation is <em>PV</em> = <em>C</em>
<em>T = C </em> for isothermal process
Calculating for the work done in isothermal process
<em>W</em> = <em>P</em>₁<em>V</em>₁ ![ln[\frac{P_{1} }{P_{2} }]](https://tex.z-dn.net/?f=ln%5B%5Cfrac%7BP_%7B1%7D%20%7D%7BP_%7B2%7D%20%7D%5D)
= <em>mRT</em>₁
[∵<em>pV</em> = <em>mRT</em>]
= (5) (0.287) (272.039) ![ln[\frac{2.0}{1.0}]](https://tex.z-dn.net/?f=ln%5B%5Cfrac%7B2.0%7D%7B1.0%7D%5D)
= 270.588 kJ
Since the process is isothermal, Internal energy change is zero
Δ<em>U</em> = 
From 1st law of thermodynamics
Q = Δ<em>U </em>+ <em>W</em>
= 0 + 270.588
= 270.588 kJ
Answer:
c. Sound travels slower than light.
Explanation:
We see any thing because of the light emitted or reflected by it. Whereas the sound is carried by the sound waves. The speed of light is more than the speed of sound. This is the reason the family saw the fireworks first and then heard the sound.
The same can be experienced during the sighting of a Jet plane or a rocket where, we see them way before we can hear the roaring sound of its engines.
Answer:

Explanation:
First step
To calculate by how much the pressure has been increased we must find a relation between Vrms and the pressure p

Where M is molar mass,R is gas constant and T is temperature
As R and M is constant so we obtain
Vrams∝√T
Second step
From Ideal gas law we know that

we will find that
p∝T
So from first and second step, we can obtain that
Vrms∝√p
And a relation between both of them could be given by:
![\frac{V_{rms1} }{V_{rms2}}=\frac{\sqrt{p_{1} } }{\sqrt{p_{2}} }\\ p_{2}=[\frac{(V_{rms1})^{2} }{(V_{rms2})^{2} }]p_{1}\\ p_{2}=\frac{(276m/s)^{2} }{(176m/s)^{2} } (2atm)\\p_{2}=4.9188atm](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7Brms1%7D%20%7D%7BV_%7Brms2%7D%7D%3D%5Cfrac%7B%5Csqrt%7Bp_%7B1%7D%20%7D%20%7D%7B%5Csqrt%7Bp_%7B2%7D%7D%20%7D%5C%5C%20%20p_%7B2%7D%3D%5B%5Cfrac%7B%28V_%7Brms1%7D%29%5E%7B2%7D%20%20%7D%7B%28V_%7Brms2%7D%29%5E%7B2%7D%20%7D%5Dp_%7B1%7D%5C%5C%20%20p_%7B2%7D%3D%5Cfrac%7B%28276m%2Fs%29%5E%7B2%7D%20%7D%7B%28176m%2Fs%29%5E%7B2%7D%20%7D%20%282atm%29%5C%5Cp_%7B2%7D%3D4.9188atm)
The pressure is increased to 4.1988 atm, so the amount will be given by:
