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Bogdan [553]
3 years ago
11

What best defines work?

Physics
1 answer:
MrRa [10]3 years ago
4 0
Moving the body to do something
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The quantity of charge q (in coulombs) that has passed through a surface of area 2.00 cm2 varies with time
Makovka662 [10]

Explanation:

We have,

Surface area, A=2\ cm^2=0.0002\ m^2

The current varies wrt time t as :

q(t) = 4t^3 + 5t + 6

(a) At t = 2 seconds, electrical charge is given by :

q(t) = 4t^3 + 5t + 6\\\\q(2) = 4(2)^3 + 5(2) + 6\\\\q=48\ C

(b) Current is given by :

I=\dfrac{dq}{dt}\\\\I=\dfrac{d(4t^3 + 5t + 6)}{dt}\\\\I=12t^2+5

Instantaneous current at t = 1 s is,

I=12(1)^2+5=17\ A

(c) Current is, I=12t^2+5

Current density is given by electric current per unit area.

J=\dfrac{I}{A}\\\\J=\dfrac{(12t^2+5)}{0.0002}\\\\J=5000(12t^2+5)\ A/m^2

Therefore, it is the required explanation.

7 0
4 years ago
an object that is 8 cm tall is located 2.5 m in front of a plane mirror. The image formed by the mirror appears to be. Find di a
UkoKoshka [18]

The image is at 2.5 m behind the mirror (virtual image)

Explanation:

We can solve the problem by using the mirror equation:

\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}

where

f is the focal length of the mirror

d_o is the distance between the object and the mirror

d_i is the distance between the image and the mirror

For a plane mirror, the focal length is infinite:

f=\infty

And in this problem, the distance of the object from the mirror is

d_o = 2.5 m

Substituting and solving for d_i, we find the location of the image:

0=\frac{1}{d_o}+\frac{1}{d_i}\\d_i = -d_o = -2.5 m

And the negative sign means that the image is located behind the mirror, so it is virtual.

Learn more about reflection and refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

6 0
3 years ago
Suppose a treadmill has an average acceleration of 4.7x10^-3 m/s. a)how much does its speed change after 5min? b)if the treadmil
Mars2501 [29]

Answer:

a)Change in the speed  = 1.41 m/s

b)The final speed will be 3.11 m/s

Explanation:

Given that

Acceleration ,a= 4.7 x 10⁻³ m/s²

a)

We know that

v= u + a t

v=final speed ,u=initial speed

t= time ,a= acceleration

Change in the speed

v- u = a t

t= 5 min  = 5 x 60 s = 300 s

v- u = 4.7 x 10⁻³ x 5 x 60 m/s

v-u = 1.41 m/s

Change in the speed  = 1.41 m/s

b)

Given that

u= 1.7 m/s

v-u = 1.41 m/s

v= 1.7 + 1.41 m/s

v=3.11 m/s

The final speed will be 3.11 m/s

8 0
4 years ago
A scientist is studying the effect on human health of bacteria that live in the human intestine. In her study, she found that th
irga5000 [103]
70 is the correct awnser
5 0
3 years ago
Read 2 more answers
Calculate the magnitude of the following vector components in OX and OY directions​
12345 [234]

Answer:

Very easy question

For x-component, we use Fₓ = Fcosα

For y-component, we use Fy = Fsinα

The major problem is with angle α.

Here α = 90+30

Because the angle is measured from +ve X-axis.

By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.

So for further calculation,

Fₓ = Fcos(90+30) = 25(-sin30)

Fₓ = -25(1/2) = 25/2 = 12.5  - will be eliminate because force in magnitude is not "-ve"

As it is

Fy = Fsin(90+30) = Fcos30

Fy = 25 (√3 /2) = 25√3/2

......................................................................................

3 0
3 years ago
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