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I am Lyosha [343]
3 years ago
12

Which component can assist in a safe stop in the event of a power outage in a pneumatic system?

Physics
1 answer:
Cloud [144]3 years ago
4 0
<span>Control valves are fundamental components of any pneumatic system. </span>Even in the event of a fault, safe exhaust of the system is ensured. The control valve can assist in safe stop in the event of a power outage in a pneumatic system.
The valve directs or blocks airflow to control the speed or sequence of operations
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_____ life cycle models of systems development assume that the scope of the project can be articulated clearly and the schedule
Natalka [10]

Answer:

Predictive

Explanation:

 There is a wide variety of life cycles applicable to project management. In this regard, we currently have as a reference two somewhat extreme approaches that mark two very different ways of dealing with projects. The predictive approach and the agile approach.

  A predictive approach involves a great effort in initial planning and re-planning every time changes are accepted in the project. Therefore, this approach is recommended for changing but not highly changing environments. Although this approach is applicable to any type of project, clear examples of application would be the construction of a subway line, a bridge, the development of critical software. That is, projects where correct and detailed planting is key.

4 0
3 years ago
Ignoring air​ resistance, an object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic mode
Lostsunrise [7]

Explanation:

Given that,

An object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic model as :

d=16t^2..........(1)

(a) We need to find the time taken by the object to fall 1148 ft. Put this in equation (1) as :

16t^2=1148

t=\sqrt{71.75}

t = 8.47 seconds

(b) If the object is in free fall for 18.5 sec after it is​ dropped, then the height of the object is given by :

d=16(18.5)^2

d = 5476 ft

Hence, this is the required solution.

7 0
4 years ago
Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it
lesya692 [45]

Answer:

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

Explanation:

As we know that the mass is revolving with constant angular speed in the circle of radius R

So we will have

\theta = \omega t

now the position vector at a given time is

r = Rcos\theta \hat i + R sin\theta \hat j

now the linear velocity is given as

v = \frac{dr}{dt}

v = (-R sin\theta \hat i + R cos\theta \hat j)\frac{d\theta}{dt}

v = R\omega(-sin\omega t \hat i + cos\omega t \hat j)

6 0
3 years ago
Find the value of T1 if 1 = 30°, 2 = 60°, and the weight of the object is 139.3 newtons.
Lelechka [254]

Answer:

Option A (69.56 newtons) is the appropriate solution.

Explanation:

According to the question,

On the X-axis,

⇒ T_1Cos30^{\circ}-T_2Cos60^{\circ}=0

or,

    T_1Cos 30^{\circ}=T_2Cos60^{\circ}

On substituting the values, we get

      T_1\times \frac{\sqrt{3} }{2}=T_2\times \frac{1}{2}

      T_1\times \sqrt{3} =T_2....(equation 1)

On the Y-axis,

⇒ T_1Sin30^{\circ}+T_2Sin60^{\circ}=139.3 \ N

                        \frac{T_1}{2} +\frac{\sqrt{3} }{2} =139.2 \ N

                    T_1+\sqrt{3}T_2=139.2\times 2

From equation 1, we get

           T_1+\sqrt{3}\times \sqrt{3}T_1 =278.4 \ N

                        T_1+3T_1=278.4 \ N

                                4T_1=278.4 \ N

                                  T_1=\frac{278.4}{4}

                                       =69.6 \ N  

6 0
3 years ago
C. 400 km/min
Nataly_w [17]
A is the answer i hope
5 0
4 years ago
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