1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NikAS [45]
3 years ago
12

Which of the following is true about chlorofluorocarbons Group of answer choices a. they are now the dominant gas in the stratos

phere b. they are very toxic to humans c.they do not exist long in the atmosphere d. they are now banned by international treaty
Chemistry
1 answer:
Gnom [1K]3 years ago
6 0

Answer:

Option (D)

Explanation:

Chlorofluorocarbon is referred to as one of the important greenhouse gas, that is responsible for the depletion of the ozone layer. It was earlier extensively used in the refrigerators, but are later observed that as the CFC molecules are disintegrated in the atmosphere, it gives rise to the elimination of chlorine atoms that destroy the ozone layer, allowing the ultraviolet radiations to enter the earth's atmosphere. So, the use of CFCs has been banned globally by international treaties.

This gas is long-lasting, and remains in the atmosphere for about 20 to 100 years, is not that effective to human bodies, and present in the stratosphere in a very small amount.

Thus, the correct answer is option (D).

You might be interested in
Our _____________ is affected by physical environment.
LekaFEV [45]

Answer:

C

Explanation:

6 0
3 years ago
Read 2 more answers
0.052301 km significant figures
lesya [120]

Answer:

Five significant figures.

Explanation:

The given measurement have five significant figures 52301.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

3 0
3 years ago
Calculate the initial rate for the formation of c at 25 ∘c, if [a]=0.50m and [b]=0.075m
Nataly_w [17]
The rate of formation of a product depends on the the concentrations of the reactants in a variable way.

If two products, call them A and B react together to form product C, a general equation for the formation of C has the form:

rate = k*[A]^m * [B]^n

Where the symbol [ ] is the concentration of each compound.

Then, plus the concentrations of compounds A and B you need k, m and n.

Normally you run controled trials in lab which permit to calculate k, m and n .

Here the data obtained in the lab are:

<span>Trial      [A]      [B]         Rate </span><span>
<span>            (M)     (M)          (M/s) </span>
<span>1         0.50    0.010      3.0×10−3 </span>
<span>2         0.50    0.020       6.0×10−3 </span>
<span>3         1.00 0  .010       1.2×10−2</span></span>


Given that for trials 1 and 2 [A] is the same you can use those values to find n, in this way

rate 1 = 3.0 * 10^ -3 = k [A1]^m * [B1]^n

rate 2 = 6.0*10^-3 = k [A2]^m * [B2]^n

divide rate / rate 1 => 2 = [B1]^n / [B2]^n

[B1] = 0.010 and [B2] = 0.020 =>

6.0 / 3.0  =( 0.020 / 0.010)^n =>

2 = 2^n => n = 1

 
Given that for data 1 and 3 [B] is the same, you use those data to find m

rate 3 / rate 1 = 12 / 3.0   = (1.0)^m / (0.5)^m =>

4 = 2^m => m = 2

Now use any of the data to find k

With the first trial: rate = 3*10^-3 m/s = k (0.5)^2 * (0.1) =>

k = 3.0*10^-3 m/s / 0.025 m^3 = 0.12 m^-2 s^-1

Now that you have k, m and n you can use the formula of the rate with the concentrations given

rate = k[A]^2*[B] = 0.12 m^-2 s^-1 * (0.50m)^2 * (0.075m) = 0.0045 m/s = 4.5*10^=3 m/s

Answer: 4.5 * 10^-3 m/s
8 0
3 years ago
Read 2 more answers
Enlista cuatro compuestos del carbono,naturales y sintéticos,de uso en la vida cotidiana.
Mice21 [21]
Below is the list of both Natural and Synthetic compounds containing Carbon.

Natural Compounds Containing Carbon:

          1) Food:
                       Carbohydrates, Proteins, Lipids, Fibers

          2) Clothing:
                        Silk, Wool, Cotton

          3) Transportation:
                                      Coal, Natural Gas, Petroleum

          4) Wood:
                        Building, Furniture

Synthetic Compounds Containing Carbon:

          1) Clothing:
                              Nylon, Polyester, 

          2) Transportation:
                                      Petrol, Diesel, Jet Fuels

          3) Building:
                           High Density Polyethylene, Polyvinyl Chloride

          4) Home Appliances:
                        Teflon in non-stick Pans, polyethylene terephthalate bottles


          
5 0
3 years ago
Read 2 more answers
PLEAEEEE HELPPP
alexgriva [62]
Speed is a scalar quantity( quantity having only magnitude). So it doesn't specifies direction. Hence option C.) 5Km/hr north is incorrect.
8 0
3 years ago
Other questions:
  • Which liquid would be the most difficult to raise or lower the temperature of
    13·2 answers
  • I need help with the bottom one plz and thxs
    12·1 answer
  • Look at the graph below. Which statement is TRUE based on the graph of an egg drop experiment? A.The egg is not accelerating. B.
    14·2 answers
  • Which bond pair does not have a polar covalent bond? P – Cl O – H S – Cl H – Cl Cl – Cl
    15·1 answer
  • An unknown compound has the following chemical formula:
    14·1 answer
  • Which element is more metallic among beriliyum or calcium? Give reason
    7·1 answer
  • Help No links Temperate grasslands are a division of a larger biome grouping of v grasslands that includes Tropical
    8·2 answers
  • What best describes the reactants and products in a reaction at equilibrium?
    15·1 answer
  • Have you ever eaten a coin?
    12·1 answer
  • How many grams are in 3.4 moles of Lead (IV) Sulfate (Pb(SO4)2)? ) Molar mass: 303.26 g/mol 131.0840​
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!