Answer:
5.46 M
Explanation:
First, we need to know the molar mass of the citric acid, the molar masses of the elements are:
H = 1 g/mol
C = 12 g/mol
O = 16 g/mol
So the molar mass of the acid is: 8x1 + 6x12 + 7x16 = 192 g/mol
The mass of the acid is the number of moles multiplied by the molar mass, so:
m = 0.688x192 = 132.096 g
Then, the volume is the mass divided by the concentration:
V = 132.096/1.049 = 125.926 mL = 0.1259 L
So, the molar concentration is the number of moles divided by the volume in liters:
M = 0.688/0.1259
M = 5.46 M
Answer:
What are we supposed to do
Explanation:
Answer:
![m_{O_2}=21.7gO_2](https://tex.z-dn.net/?f=m_%7BO_2%7D%3D21.7gO_2)
Explanation:
Hello,
In this case, with the given chemical reaction, the stoichiometry applies for the resulting mass of oxygen as shown below:
![m_{O_2}=55.3gKClO_3*\frac{1molKClO_3}{122.55 gKClO_3}*\frac{3molO_2}{2molKClO_3}*\frac{32gO_2}{1molO_2} \\m_{O_2}=21.7gO_2](https://tex.z-dn.net/?f=m_%7BO_2%7D%3D55.3gKClO_3%2A%5Cfrac%7B1molKClO_3%7D%7B122.55%20gKClO_3%7D%2A%5Cfrac%7B3molO_2%7D%7B2molKClO_3%7D%2A%5Cfrac%7B32gO_2%7D%7B1molO_2%7D%20%5C%5Cm_%7BO_2%7D%3D21.7gO_2)
Best regards.
Answer:
It is an area that is covered in grasses and wildflowers that receives enough rainfall to support the grassland but not the growth of trees.
Explanation:
Soap is the sodium or potassium salt of long chain of fatty acid. Fatty acids when treated with NaOH or KOH forms Soap. This process is called as Saponification. Examples of Soap are as follow,
1. Sodium Stearate C₁₇H₃₅COONa
2. Potassium Oleate C₁₇H₃₃COOK
Reaction of Soap with MgCl₂;
When Soap is treated with MgCl₂ or CaCl₂ it forms insoluble precipitate called S.C.U.M. The reactions with MgCl₂ are as follow,
2C₁₇H₃₅COONa + MgCl₂ --------> 2C₁₇H₃₅COOMg + 2 NaCl
2C₁₇H₃₃COOK + MgCl₂ --------> 2C₁₇H₃₅COOMg + 2 KCl
These reaction are often found in hard water. And this reaction decreases the effectiveness of soap.