Molar mass of butane = 12g/mol*4+1g/mol*10=58g/mol
Mass of 2 moles of butane=2mol*58g/mol=116g
2c4h10(g)+13o2(g)->8co2(g)+10h2o(l)
<span>116g 8 moles</span>
<span>3.20g x</span>
116g butane/8moles CO2=3.20g butane/x
x=3.20g butane*8moles CO2/116g butane=0.2207moles CO2
T=23°C=296K
PV=nRT
V=nRT/P=0.2207moles*0.082(atm*dm³/(K/mol))*296K/(1atm)=5.36dm³
1.
n = m/2.016 g/mol = V/22.4 l
V = 22.4 l
Hence,
m = 2.016 g ≈ 2.02 g
B.) 2.02 g
2.
Balancing the equation, we get,
Mg + 2HCl → MgCl2 + H2
PV = nRT
V = nRT/P
V = 1.5 mol × 8.314 atm/(mol.K) × 298 K/(0.96 atm)
V = 3871.206
V ≈ 38.2 l
Answer:
Allison walks 5 blocks west and 3 blocks south.
Explanation:
Vectors have both magnitude and direction. The attached figure shows the graph of Allison’s walk to school. She follows the black vectors to get to her school.
The first vector on the horizontal axis points towards west and there are 5 blocks. Initially, she walks 5 blocks in west direction.
The second vector points in the negative vertical axis. It means that she walks 3 block in south direction.
Hence, the correct option is (D) i.e. Allison walks 5 blocks west and 3 blocks south.
Substances that posses an excess it greater amount of hydroxide ions are considered basic, or alkali like in solution. They would thus showcase properties of a basic substance.
<h3>Answer:</h3>
1.0 × 10⁻⁶ M (Option-A)
<h3>Solution:</h3>
Data Given:
pH = 6
[H⁺] = ?
Formula Used:
As we know pH is given as,
pH = -log [H⁺]
and,
[H⁺] = 10^-pH ----- (1)
Putting value of pH in eq. 1,
[H⁺] = 10⁻⁶ ∴ 10 = Antilog
[H⁺] = 1.0 × 10⁻⁶ M
