Ask question

Ask question

All categories

3 years ago

10

Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equat

ion?

1 answer:

ss7ja [257]3 years ago

5 0

8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
4*2=8
1*2=2
3*2=6

You might be interested in

Every organism is an ecosystem receives energy from another source.Which of these organism receives its energy directly from the

Fed [463]

Answer:

The answer is grass

Explanation:

Grass is a plant, meaning it undergoes photosynthesis to receive its energy from the sun.

5 0

3 years ago

Read 2 more answers

Which is an example of a heterogeneous catalyst?

N76 [4]

An example of a heterogeneous catalyst is a catalytic converter. A catalytic converter is an emissions control device that converts toxic pollutants in exhaust gas to less toxic pollutants by catalyzing a redox reaction (oxydation or reduction).

8 0

3 years ago

Read 2 more answers

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

$Q_1=m\times \Delta H_{fusion}$

where,

$Q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

$\Delta H_{fusion}$ = enthalpy change for fusion = $3.35\times 10^5J/Kg$

Now put all the given values in $Q_1$ , we get:

$Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J$

<u>For process 2 :</u>

$Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})$

where,

$Q_2$ = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

$c_{p,l}$ = specific heat of liquid water = $4186J/Kg^oC$

$T_1$ = initial temperature = $0^oC$

$T_2$ = final temperature = $100^oC$

Now put all the given values in $Q_2$ , we get:

$Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC$

$Q_2=4.186\times 10^5J$

From this we conclude that, $Q_1$ that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0

3 years ago

How many protons electrons and neutrons respectively does 29 CS have

irakobra [83]

$55 \; \text{e}^{-}$ , $55 \; \text{p}^{+}$ , and $74 \; \text{n}^{0}$ - in case cesium-129 is what you were referring to.

Cesium has atomic number $55$ as seen on a modern periodic table. A cesium atom nucleus would thus contain an equal number of protons; in addition to that, a <em>neutral</em> atom of cesium would contain the same number of electrons in its electron cloud.

For a particular isotope,

$\text{Mass number} = \text{Number of protons per nuclei} + \text{Number of Neutrons per nuclei}$ .

This isotope of cesium has a mass number of $129$ and contains $55$ protons in each atomic nucleus. One cesium nuclei would therefore contain $129 - 55 = 74$ neutrons.

8 0

3 years ago

7. The smallest representation of an lonic compound is

BlackZzzverrR [31]

Answer:

c Formula unit

hope this helped

3 0

3 years ago