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Sauron [17]
3 years ago
10

Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equat

ion?
Chemistry
1 answer:
ss7ja [257]3 years ago
5 0
8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
4*2=8
1*2=2
3*2=6
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Svetach [21]
1 mole Hg --------------- 6.02x10²³ atoms
?? moles Hg ------------ 1.30x10⁷ atoms

(1.30x10⁷) x 1 / 6.02x10²³ => 2.159x10⁻¹⁷ moles 
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What's the definition if blood
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8 0
3 years ago
I need some help on this.
Orlov [11]

Answer:

I think the right answer is c/ number of atomic orbitals

5 0
3 years ago
Read 2 more answers
Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.
BlackZzzverrR [31]

Answer:

510 g NO₂

General Formulas and Concepts:

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
  • Reading the Periodic Table
  • Writing Compounds
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

<u>Step 3: Use Dimensional Analysis</u>

<u />6.7 \cdot 10^{24} \ molecules \ NO_2(\frac{1 \ mol \ NO_2}{6.022 \cdot 10^{23} \ molecules \ NO_2} )(\frac{46.01 \ g \ NO_2}{1 \ mol \ NO_2} ) = 511.901 g NO₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

511.901 g NO₂ ≈ 510 g NO₂

6 0
3 years ago
Please help, I lost my previous tutor just when she was explaining the answer
TEA [102]

Answer:

HCO₂/H₂O is not the acid-base conjugate pair.

Explanation:

<em>Acid and conjugate base pairs differ by an H+ ion.</em>

Neither HCO₂ nor H₂O has lost or gained protons.

The conjugate acid of H₂O is H₃O⁺

The conjugate base of HCO₃⁻ is CO₃²⁻

[A conjugate acid has one more H⁺ than its base]

5 0
2 years ago
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