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Advocard [28]
3 years ago
14

In witch step did a chemical change most likely occur

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

step 2

hope this helps!

please mark as brainiest<3

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Which one of the following frequencies of a wave in the air can be heard has an audible sound by the human ear
yulyashka [42]
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6 0
3 years ago
3 Na2O(aq) + 2 Al(NO3)3(aq) ----&gt; _ Compound A + _ Compound B
Olin [163]
3Na2O(at) + 2Al(NO3)3(aq) —> 6NaNO3(aq) + Al2O3(s)

This is a double replacement reaction and NaNO3 is aqueous because Na is an alkali metal, plus nitrate is in the solution. Both of these are soluble. Al2O3 is not soluble because it does not contain any element that is soluble and is hence the precipitate.

Hope this helped!
7 0
3 years ago
What is the mole ratio that can convert from moles of A to moles of B?
kaheart [24]
There is no direct way to convert from the mass of one substance to the mass of another. To convert from one mass (substance A) to another mass (substance B), you must convert the mass of A first to moles, then use the mole-to-mole conversion factor (B/A), then convert the mole amount of B back to grams of B.
8 0
3 years ago
If a chemical is oxidized it is also known as the
RUDIKE [14]

Answer:

D.) reducing agent

Explanation:

Oxidized chemicals gain electrons. In order to gain these electrons, another chemical must lose electrons. So, the chemical (which will be oxidized) acts as a reducing agent, causing the other chemical to be reduced and lose electrons.

4 0
2 years ago
A typical carbon monoxide detector will sound it's alarm if it detects 0.050 g of CO, HOw many molecules of carbon monoxide are
Colt1911 [192]

Answer:

1.07×10²¹ molecules are needed to sound the alarm

Explanation:

Let's convert the mass of CO to moles, to determine the amount of molecules.

0.05 g . 1 mol / 28 g = 1.78×10⁻³ moles

Now we can determine the number of molecules with the NA

1 mol has 6.02×10²³ molecules

1.78×10⁻³ moles may have (1.78×10⁻³ .  6.02×10²³) / 1 = 1.07×10²¹ molecules

4 0
3 years ago
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