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Basile [38]
3 years ago
15

True or False: All material has the same density.

Chemistry
2 answers:
AlexFokin [52]3 years ago
8 0

Answer:

The answer is False

Burka [1]3 years ago
4 0

Answer:

Different materials have different densities. So it is False

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Which factor is a measure of the oxygen in a body of water?
KATRIN_1 [288]
B. Dissolved Oxygen

is a measure of the oxygen in a body of water.
6 0
3 years ago
Magnesium (Mg) reacts with chlorine gas (Cl2) to produce magnesium chloride (MgCl2). How many grams of Mg will reacts with 2 mol
Rom4ik [11]
Mg   +   Cl₂ -----> MgCl₂
24g     1 mol


24g Mg ---- 1 mol Cl₂
Xg Mg ------ 2 mol Cl₂
X = 2×24
<u>X = 48g Mg</u>
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7 0
3 years ago
What is the oxidation state of Hydrogen in H20<br><br> +2<br> +1<br> -2<br> -1
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<h3>What is the oxidation number of oxygen in H2O?</h3>

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6 0
2 years ago
Convert 20 cals to J
zimovet [89]

Answer: 83.68 J

Explanation:

1 cal=4.184 J

1×20=4.184×20

20cals=83.68 J

8 0
3 years ago
Consider the solubilities of a particular solute at two different temperatures. Temperature ( ∘ C ) Solubility ( g / 100 g H 2 O
grin007 [14]

Answer:

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Explanation:

Solubility of solute at 20°C = 32.2 g/100 grams of water

Solute soluble in 1 gram of water = \frac{32.2}{100}g=0.322 g

Mass of solute in soluble in 56.0 grams of water:

0.322\times 56.0=18.032 g

Solubility of solute at 30°C = 70.2g/100 grams of water

Solute soluble in 1 gram of water = \frac{70.2}{100}g=0.702 g

Mass of solute in soluble in 56.0 grams of water:

0.702 \times 56.0=39.312 g

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C

Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g

Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g

Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:

39.312 g - 18.032 g = 21.28 g

21.28 grams solute can be added if the temperature is increased to 30.0°C.

8 0
3 years ago
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