Answer:
a) before immersion
C = εA/d = (8.85e-12)(25e-4)/(1.31e-2) = 1.68e-12 F
q = CV = (1.68e-12)(255) = 4.28e-10 C
b) after immersion
q = 4.28e-10 C
Because the capacitor was disconnected before it was immersed, the charge remains the same.
c)*at 20° C
C = κεA/d = (80.4*)(8.85e-12)(25e-4)/(1.31e-2) = 5.62e-10 F
V = q/C = 4.28e-10 C/5.62e-10 C = 0.76 V
e)
U(i) = (1/2)CV^2 = (1/2)(1.68e-12)(255)^2 = 5.46e-8 J
U(f) = (1/2)(5.62e-10)(0.76)^2 = 1.62e-10 J
ΔU = 1.62e-10 J - 5.46e-8 J = -3.84e-8 J
Answer:
a) If the thermometer is placed well below the condenser it will record a higher temperature.
b) If the thermometer is placed well above the condenser it will record a lower temperature.
Explanation:
A) ) If the thermometer is placed below the opening to the condenser, a higher temperature will be recorded than if it is placed close to the opening since the bulb is contact with both the vapuor and liquid that is entering the condenser.
B) If the thermometer is placed above the condenser, a lower temperature will be recorded than if it is placed close to the opening since the bulb is not in full contact with both the vapuor and liquid that is entering the condenser.
Complete question is;
Marie observed people at a store. Which is a qualitative observation she may have made?
A. Twenty people walked into the store.
B. The store sells clothes.
C. It was 1:00 P.M.
D. all of the above
Answer:
Option B:The store sells clothes.
Explanation:
We want to find the one that is a qualitative observation;
Looking at the options;
A. Twenty people walked into the store. This denotes a quantitative measure because of the number 20.
B. The store sells clothes. This denotes a qualitative measure because it describes what she sells.
C. This is a quantitative measure because it deals with time of 1 pm which is quantitative.
Therefore, the correct answer is Option B
A saturated solution is one that cannot dissolve any more of the substance that is mixed into it.
Answer:
Explanation:
<u>Functions</u>
When one magnitude depends on other (or others), we usually try to express them as a function which can contain any number of variables, constants, and operations.
The area of a circle is computed by the well-known formula
We are required to use function notation to express the area of a circle f(r) in terms of the radius r. If the radius is in cm, then the area is in 
.
The required function is
For a radius of 4.3 cm:
