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agasfer [191]
3 years ago
9

Please help I’m struggling

Physics
2 answers:
spin [16.1K]3 years ago
7 0
The correct answer is B
prisoha [69]3 years ago
4 0

Answer:

B

Explanation:

Hope it helps!:)

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Building helps children develope their _____ skills
Musya8 [376]

Answer:

I'll say number sense and operation

Explanation:

this is because it will show how creative and Intelligent that child is,and it will help increase thier brain functions

3 0
3 years ago
Read 2 more answers
A puck of mass m moving at speed v on a horizontal, frictionless surface is stopped in a distance d because a hockey stick exert
MArishka [77]

Answer:

-36.71%

Explanation:

Using the Generalized Work Energy Principle, the puck is brought to rest by an external force and the system has no kinetic energy

U_i+W=U_f\\K_i+W=K_f\\\\0.5mv_i^2+F\bigtriangleup xcos\theta=0J\\\\0.5mv_i^2+F\bigtriangleup xcos180\textdegree=0J\\\\0.5mv_i^2=F\bigtriangleup x\\\\F=\frac{0.5mv_i^2}{2\bigtriangleup x}

#Denote the stopping distance and force required with a prime and observe from (i) that:

F\infty\frac{1}{\bigtriangleup x}\\\\F\prime =F.\frac{\bigtriangleup x}{(\bigtriangleup x)\prime}\\\\  #If stopping distance increases by a factor of 79/50;

F\prime=F.(79/50)^-^1\\\\F\prime=\frac{50F}{79}\\\\\therefore \bigtriangleup F=F\prime -F\\\\\bigtriangleup F=\frac{50F}{79}-F=-\frac{29F}{79}

So F decreases by 36.71% . we expect force to reduce since the same amount of work is repeatedly done on the system over a long distance.

8 0
4 years ago
A ball with a mass of 0.25 kg hits a gym ceiling with a force of 78.0 n. what happens next?
QveST [7]
<span>a. The ball accelerates downward with a force of 80.5 N. This is a rather badly worded question since the answer depends upon whether or not the impact with the gym ceiling was elastic or non-elastic. With an elastic collision, the ball will accelerate downward with it's original force plus the acceleration due to gravity. With a non-elastic collision (the energy in the ball being used to damage the ceiling of the gym), then the initial energy the ball has would be expended while causing damage to the gym ceiling and then the ball would accelerate downward solely due to the force of gravity. In either case, we need to take into consideration the force of gravity. So multiply the mass of the ball by the gravitational acceleration, giving F = 0.25 kg * 9.8 m/s^2 = 2.45 kg*m/s^2 = 2.45 N Since the initial force is 78.0 newtons, let's add them 78.0 N + 2.45 N = 80.45 N and after rounding to 3 figures, gives 80.5 N So we have a possible answer of 2.45N or 80.5N depending upon if the collision is elastic or not. And unfortunately, both possible answers are available. Since no mention of the ceiling being damaged is made in the question, and to be honest a 100% non-elastic collision is highly unlikely, I will assume the collision is elastic, so the answer is "a".</span>
6 0
3 years ago
A torque acts on a wheel rotating at 19.8 rad/s and increases its angular speed to 23.5 rad/s in 11.2 s. Find the angle through
faltersainse [42]

243 rad is the angle through which the wheel turns during this time.

<h3>What is torque and angular speed?</h3>

Torque is a measure of the force that can cause an object to rotate about an axis.

Angular speed is define as  the measuring angle of rotation over a given amount of time.

Mathematically , ω = θ t

From the given question ,

Torque = 19.8 rad/s

ω = 23.5 rad/s

t = 11.2 s

We get the equation,

\frac{ 19.8 +23.5}{2} * 11.2

= 243 rad

Learn more about Angular momentum here:

brainly.com/question/15104254

#SPJ1

7 0
2 years ago
A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 15.6
VladimirAG [237]

To solve this problem it is necessary to take into account the kinematic equations of motion and the change that exists in the volume flow.

By definition the change in speed is given by

v_f^2-v_i^2 = 2ax

Where,

x= distance

v_f =final velocity

v_i =initial velocity

a = acceleration

On the other hand we know that the flow of a fluid is given by

\dot{V} = Av

Where,

A = Area

v = Velocity

PART A )

Applying this equation to the previously given values we have to

v_f^2-v_i^2 = 2ax

v_f^2-0 = 2*(9.8)(15.6)

v_f^2=305.76

v_f = 17.48

Therefore the velocity of the water leaving the hole is 17.48m/s

PART B )

In the case of the hole we take the area of a circle, therefore replacing in the flow equation we have to,

\dot{V} = \pi r^2 v

r = \sqrt{\frac{\dot{V}}{\pi v}}

r = \sqrt{\frac{3*10^{-3}*\frac{1}{60}}{\pi (17.48)}

r = \sqrt{9.10*10^{-7}}

r = 0.54*10^{-4}

The diameter is 2 times the radius, then is 1.91*10^{-3}m or 1.91mm

<em>Note: The rate flow was converted from minutes to seconds.</em>

8 0
3 years ago
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