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3 years ago

Mercury is 0.39 AU from the sun what is its distance from the sun in kilometers

Physics

2 answers:

marissa [1.9K]3 years ago

5 0

Answer:The distance of Mercury from the Sun in kilometer is $5.8344\times 10^7 km$ .

Explanation;

Distance between the Mercury and Sun = 0.39 AU

1 AU = $1.496\times 10^8 km$

So, 0.39 AU = $0.39\times 1.496\times 10^8 km=5.8344\times 10^7 km$

The distance of Mercury from the Sun in kilometer is $5.8344\times 10^7 km$ .

lutik1710 [3]3 years ago

3 0

58,000 --------------------------------------------------------------

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A 90 kg ice skater moving at 12.0 m/s on the ice encounters a region of roughed up ice with a coefficient of kinetic friction of

balandron [24]

Answer:

The skater covers a distance of <u>15 m</u> before stopping.

Explanation:

Let the distance traveled before stopping be 'd' m.

Given:

Mass of the skater (m) = 90 kg

Initial velocity of the skater (u) = 12.0 m/s

Final velocity of the skater (v) = 0 m/s (Stops finally)

Coefficient of kinetic friction (μ) = 0.490

Acceleration due to gravity (g) = 9.8 m/s²

Now, we know that, from work-energy theorem, the work done by the net force on a body is equal to the change in its kinetic energy.

Here, the net force acting on the skater is only frictional force which acts in the direction opposite to motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force acting on the skater. As there is no vertical motion, $N=mg$

∴ $f=\mu mg=0.490\times 90\times 9.8=432.18\ N$

Now, work done by friction is a negative work as friction and displacement are in opposite direction and is given as:

$W=-fd=-432.18d$

Now, change in kinetic energy is given as:

$\Delta K=\frac{1}{2}m(v^2-u^2)\\\\\Delta K=\frac{1}{2}\times 90(0-12^2)\\\\\Delta K=45\times (-144)=-6480\ J$

Therefore, from work-energy theorem,

$W=\Delta K\\\\-432.18d=6480\\\\d=\frac{6480}{432.18}\\\\d=14.99\approx 15\ m$

Hence, the skater covers a distance of 15 m before stopping.

7 0

3 years ago

What are the laws of Physics

uranmaximum [27]

Answer:

thermodynamics

Explanation:

The laws of thermodynamics define a group of physical quantities, such as temperature, energy, and entropy, that characterize thermodynamic systems in thermodynamic equilibrium.

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3 years ago

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous plan

Elan Coil [88]

Answer:

Scientists plan to release a space probe that will enter the atmosphere of a gaseous planet. The temperature of the gaseous planet increases linearly with the height of the atmosphere as measured from the top of a visible boundary layer, defined as 0 kilometers in altitude. The instruments on board can withstand a temperature of 601 K. At what altitude will the probe's instruments fail? A. 50 kilometers B. 80 kilometers C. 83 kilometers D. 100 kilometers E. 111 kilometers

Explanation:

A. 50 kilometers

8 0

3 years ago

Find the frequency if the period is 15 us.

Sav [38]

Answer:

The frequency is $0.667$ × $10^{6}$ $Hz$ .

Explanation:

Period is defined as the time taken by any element to attempt one complete oscillatory motion in one second.
Frequency is the number of complete oscillations made in one second.