Answer:
Explanation:
Given that,
Charge density is λ = 12 nC/m
And radius 3cm
r=0.03m.
The charge density of a along a circular arc is given as
λ= Q/πr
Then, Q=πrλ
Q=π×0.03×12×10^-9
Q=1.131×10^-9 C
Q=1.131 nC
Then, electric field along x axis is symmetrical and if cancels out
Now, Ey is in the negative direction
Electric field is given as,
Ey=-2kQ/πr²
K is constant =9×10^9Nm²/C²
Ey=-2×9×10^9×1.131×10^-9/(π ×0.03²)
Ey=7200 N/C.
The direction is negative direction of y axis, check attachment for diagram.
b. Electric potential at the origin is given as
V=Ed
d=r=0.03
V=7200×0.03
V=216V
Answer:
F = 614913.88 N
Explanation:
We are given;
Mass of pile driver; m = 1800 kg
Height of fall of pole driver; h = 4.6 m
Depth driven into beam; d = 13.6 cm = 0.136 m
Now, from energy equations and applying to this question, we can write that;
Workdone = Change in potential energy
Formula for workdone is; W = F × d
While the average potential energy here is; W = mg(h + d)
Thus;
Fd = mg(h + d)
Where F is the average force exerted by the beam on the pile driver while in bringing it to rest.
Making F the subject, we have;
F = mg(h + d)/d
F = 1800 × 9.81 × (4.6 + 0.136)/0.136
F = 614913.88 N
Answer:
$893
Explanation: the complete question should be
The clothes washer in your house consumes 470 kWh of energy per year. Price of the washer is $360 and the lifetime of the washer is 10 yrs. Energy price in your city is 9 cents per kWh. What is the lifecycle cost of the clothes washer? (assume a maintenance cost of $11 per year)
SOLUTION
Given:
The clothes washe power consumption (PC) is 470 kWh
Price of the washer (P) is $360
lifetime of the washer (L) is 10 yrs
Energy price in the city (E) is 9 cents per kWh (Covert to $ by dividing 100)
maintenance cost (M) is $11 per year
Lifecycle cost = P + (PC × L × E) +M + L
Lifecycle cost = $360 + (470kWh × 10years × 9cents/100) + ($11 × 10years)
=$893
Protective Factors is the term taken.
Answer:
Explanation:
Kinetic energy at the height = 1/2 m v²
= 1/2 x 750 x 20²
= 150000 J
Its potential energy = mgh
= 750 x 9.8 x 5
=36750 J
Total energy = 186750 J
Its total kinetic energy will be equal to 186750 J , according to conservation of mechanical energy
If v be its velocity at the bottom
1/2 m v² = 186750
v = √498
= 22.31 m /s
