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Fantom [35]
3 years ago
10

Moon does not have atmosphere as we have on Earth. On the earth, you can see the ground in someone’s shadow; on the moon, you ca

n’t—the shadow is deep black. Explain the scientific reason behind this difference
Physics
1 answer:
bazaltina [42]3 years ago
5 0

One of the scientific characteristics that can make the difference between the Earth and the moon is the so-called Rayleigh dispersion effect. This concept is identified as the dispersion of visible light or any other electromagnetic radiation by particles whose size is much smaller than the wavelength of the dispersed photons. Our atmosphere allows even our 'shadows' to be clear.

On the moon under the absence of the atmosphere or any other mechanism that allows absorbing or failing to re-irradiate sunlight towards the area in its shadows, which makes the shadows on the moon look darker.

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4 0
3 years ago
A daring 510N swimmersdives off a cliff with a running horizontal lead.what must be her mimimum speed just as she leaves the top
goldfiish [28.3K]

Answer:

The running horizontal speed should be larger than 1.29 m/s.

Explanation:

In order for the swimmer to just miss the bone-breaking ledge, her horizontal speed must be

v > \frac{1.75m}{t_{fall}}

in which we need to know how long we she be diving through the air. To determine that, recall the formula for the distance made by an object with acceleration (in this case it is the gravitational acceleration) with no initial (vertical) velocity:

s = \frac{1}{2}gt^2

from which it follows that (for non-negative t)

t = \sqrt{\frac{2\cdot9m}{9.8\fram{m}{s^2}}}\approx1.36s

This result can be used in the initial inequality:

v > \frac{1.75m}{t_{fall}}=\frac{1.75m}{1.36s}=1.29\frac{m}{s}

The diving lady better gets a speed larger than 1.29 m/s to avoid landing on the ledge.

8 0
3 years ago
Read 2 more answers
A diver shines a flashlight upward from beneath the water (n = 1.33) at a 32.7° angle to the vertical. At what angle does the li
suter [353]

Answer:

45.93°

Explanation:

The angle of incidence is given as 32.7°

The refractive index of the water that is n_1=1.33

Refractive index of the air that is n_2=1 (because the refractive index of air is 1 )

We have to find the angle at which the light leave the water means angle of refraction

So according to snell's law n_1sini=n_2sinr

1.33sin32.7=1\times sinr

sinr=0.7185

r =45.93°

So the light leave the water at an angle of 45.93°

3 0
3 years ago
What would be the speed of an object just before hitting the ground if dropped 91.5 meters
Aleks04 [339]

Answer:

about 42.35 m/s

Explanation:

Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:

v_f^2=v_i^2+2\,a\,\Delta x

which for our case would reduce to:

v_f^2=v_i^2+2\,a\,\Delta x\\v_f^2=0+2\,9.8\,(91.5)\\v_f^2= 1793.4\\v_f=\sqrt{1793.4} \\v_f \approx 42.35

then the velocity just before hitting would be about 42.35 m/s

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3 years ago
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