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tankabanditka [31]
3 years ago
14

An airtight box has a removable lid of area 1.00 10-2 m2 and negligible weight. the box is taken up a mountain where the air pre

ssure outside the box is 9.50 104 pa. the inside of the box is completely evacuated. what is the magnitude of the force required to pull the lid off the box
Physics
1 answer:
gladu [14]3 years ago
8 0
<span>9.50x10^2 newtons A pascal is defined as 1 newton per square meter. So let's multiply the pressure by the surface area of the box lid. F = 1.00x10^-2 m^2 * 9.50x10^4 N/m^2 = 9.50x10^2 N So it will take 9.50x10^2 newtons of force to remove the lid from the box.</span>
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Complete Question

A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.

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(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP

Answer:

a

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  COP_1 = 9.49  

Explanation:

From the question we are told that

     The lower operation temperature of refrigerator is  T_1 =  -8.00^oC =  265 \  K

     The upper operation temperature of the refrigerator is   T_2 =  23.2 ^oC =  296.2 \  K

Generally the refrigerators coefficient of performance is mathematically represented as

        COP =  \frac{T_1}{T_2 - T_1  }

=>     COP =  \frac{265}{296.2 - 265  }

=>     COP = 8.49

Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as

            COP_1 =  \frac{T_2}{ T_2 - T_1}  

=>         COP_1 =  \frac{296.2}{ 296.2 - 265 }  

=>         COP_1 = 9.49  

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