Answer:
All the observers are correct.
Explanation:
This is simply a problem of reference frames from which the motion of the book is being viewed by the various observers.
From their various reference frames, they are all correct.
Observer A must be in the inertial reference frame.
<em>Observers who can explain the behavior of the book and the car by using the relationship between the sum of the forces and changing velocity are said to be observers in inertial reference frames.</em>
This is clearly shown by what observer A noticed. There was a relative motion between the book and the car as she pointed out, making her to be in an inertial reference frame.
<em>Similarly, observers in inertial reference frames can also explain the changes in velocity of objects by considering the forces exerted on them by other objects.</em>
This is shown by observer B as he is able to notice how the force of the car affects the velocity of the book.
Observer C is actually in a non-inertial reference frame, as newtons law of force motion relationship are no longer observed. This occurs in the non inertial reference frame.
Answer:
Answer:
4, 2, 5, 3, 1
Explanation:
The neuron remains at RMP unless stimulated. The stimulus results in opening of stimulus channels, this causes depolarization. if the extent of depolarization reaches to the level of threshold, the sodium and potassium channels begin opening but potassium channels are slow to open. Hence at first sodium goes out causing further depolarization until it reaches the peak at which the potassium channels open and the sodium channels close. This causes the potassium to rush our causing repolarization i.e. return of the membrane potential to RMP but the potassium channels are slow to close and it leads to hyperpolarization (undershoot) making the membrane potential more negative due to excessive movement of potassium outside the cell. Once the potassium channels close, the leak channels and Na K pump acts to return the potential to RMP.
Explanation:
P=IV
P=15KW=15000W
V=300
I=P/V
I=15000/300
I=50 Ampere
