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kodGreya [7K]
3 years ago
5

PLEASE HURRYWhich relation is a function?

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

Answer:

This one (look at the attachment)

Step-by-step explanation:


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Segment AB has endpoints A(-1,3) and B(0,7). What is the length of AB?
ololo11 [35]

Answer:

\sqrt{17}

Step-by-step explanation:

Calculate the length (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1, 3) and (x₂, y₂ ) = (0, 7)

d = \sqrt{(0+1)^2+(7-3)^2}

   = \sqrt{1^2+4^2}

   = \sqrt{1+16}

   = \sqrt{17} ≈ 4.1 ( to 1 dec. place )

5 0
3 years ago
If 3a+4a=14, and b+6b=21, then 7(a+b) =<br><br> Help and show work!
den301095 [7]
Hello!

You have to find what a and b are

3a + 4a = 14
b + 6b = 21

Lets do a first

3a + 4a = 14

Combine like terms

7a = 14

Divide both sides by 7

a = 2

Now lets do b

b + 6b = 21

Combine like terms

7b = 21

Divide both sides by 7

b = 3

Put a and b into the third equation

7( 2 + 3) = 

Do what is in parenthesis first

7(5) = 

Multiply

35

The answer is 35

Hope this helps!
8 0
3 years ago
Read 2 more answers
Simplify 1- cos^2 Θ / cos^2 Θ<br><br> Answers<br><br> sin2 θ<br><br> cos2 θ<br><br> tan2 θ<br><br> 1
Tems11 [23]

Answer:

<h3><u /></h3>

<u>Trigonometric identities</u>

<u />

\large \begin{aligned}\cos^2 \theta + \sin^2 \theta & = 1\\\implies \quad \quad \sin^2 \theta & = 1 - \cos^2 \theta\\\\\tan \theta=\dfrac{\sin \theta}{\cos \theta} \end{aligned}

Therefore, using the <u>identities</u>, the given expression can be <em>simplified</em> as follows:

\large\begin{aligned}\implies \dfrac{1- \cos^2 \theta}{\cos^2 \theta} & = \dfrac{\sin^2 \theta}{\cos^2 \theta}\\\\& = \tan^2 \theta\end{aligned}

3 0
2 years ago
Read 2 more answers
Match the term with the definition.
Bingel [31]

Answer:

A. Perpendicular Lines

B. Circle

C. Angle

D. Plane

E. Parallel Lines

Hope this helped! Mark as Brainliest Please! :)))

Step-by-step explanation:

8 0
3 years ago
Pls help me with this, tyyy!
Olenka [21]

Answer:

Input : 12

Output : -48

Step-by-step explanation:

Hope it helped

6 0
3 years ago
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