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3 years ago

Describe four stresses that upset the equilibrium of a chemical reaction

Chemistry

1 answer:

julia-pushkina [17]3 years ago

5 0

Answer:

Concentration, pressure, and temperature are the three factors that affect chemical equilibrium

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Liula [17]

Answer:

yes

Explanation:

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3 years ago

What is the hydrogen ion concentration of a solution with a pH of 2.0?

aliina [53]

Answer:

Knowing others is intelligence; knowing yourself is true wisdom. mastering others is strength; mastering yourself is true power. if you realize that you have enough, you are truly rich, "And the cause of not following your heart, is in spending the rest of your life wishing you had."

Explanation:

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8 0

3 years ago

How many milliliters of 0.128 M nitric acid are required to neutralize 11.1 mL of 0.184 M sodium hydroxide? Answer with the corr

Llana [10]

Answer:

I think 7.72 mL

11.1/184 × 128/184=7.72

4 0

3 years ago

What is the molar mass of C3N4? (Do NOT round this number.)

vichka [17]

Answer:

92.06 g/mol

Explanation:

4 0

3 years ago

What is the theoretical yield of aluminum oxide if 1.40 mol of aluminum metal is exposed to 1.35 mol of oxygen?

jasenka [17]

Answer:

71.372 g or 0.7 moles

Explanation:

We are given;

Moles of Aluminium is 1.40 mol
Moles of Oxygen 1.35 mol

We are required to determine the theoretical yield of Aluminium oxide

The equation for the reaction between Aluminium and Oxygen is given by;

4Al(s) + 3O₂(g) → 2Al₂O₃(s)

From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.

Therefore;

1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen

1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium

Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.

4 moles of aluminium reacts to generate 2 moles aluminium oxide.

Therefore;

Mole ratio Al : Al₂O₃ is 4 : 2

Thus;

Moles of Al₂O₃ = Moles of Al × 0.5

= 1.4 moles × 0.5

= 0.7 moles

But; 1 mole of Al₂O₃ = 101.96 g/mol

Thus;

Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol

= 71.372 g

3 0

3 years ago