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2 years ago

The existence of discrete (quantized) energy levels in an atom may be inferred from

1 answer:

8 0

<span>It can be inferred from atomic line spectra. These are certain wavelengths of light that atoms give off when they become excited. The energy levels in an atom can be proven to exist from this phenomenon, and furthermore, they can be measured.</span>

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How many moles of calcium carbonate-CaCO3 = 4.15 g

marin [14]

Answer:

Number of moles = 0.042 mol

Explanation:

Given data:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass/ molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12+ 3×16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol

3 0

3 years ago

Which protists lack cilia and flagella, but can still move around?

timama [110]

Answer: amoebae !

Explanation:

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3 years ago

What type of rock is chromium

pantera1 [17]

<span>an oxide of iron, magnesium, aluminum, and chromium</span>

7 0

2 years ago

Read 2 more answers

This worm infects humans by getting into the blood stream. It gets a

liraira [26]

Pretty sure it’s C- hope this helps❤️

5 0

2 years ago

A 100.0mL bubble of hot gases at 225 C and 1.80 atm escapes from an active volcano, what is the new volume of the bubble outside

Inessa05 [86]

<h3>Answer:</h3>

112.08 mL

<h3>Explanation:</h3>

From the question we are given;

Initial volume, V1 = 100.0 mL
Initial temperature, T1 = 225°C, but K = °C + 273.15

thus, T1 = 498.15 K

Initial pressure, P1 = 1.80 atm
Final temperature , T2 = -25°C

= 248.15 K

Final pressure, P2 = 0.80 atm

We are required to calculate the new volume of the gases;

According to the combined gas law equation;

$\frac{P1V1}{T1}=\frac{P2V2}{T2}$

Rearranging the formula;

$V2=\frac{P1V1T2}{T1P2}$

Therefore;

$V2=\frac{(1.80atm)(100mL)(248.15K)}{(498.15K)(0.80atm)}$

$V2=112.08mL$

Therefore, the new volume of the gas is 112.08 mL

8 0

3 years ago