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mote1985 [20]
1 year ago
13

Is there any industrial process that use evaporation to separate a solution?

Chemistry
2 answers:
sergiy2304 [10]1 year ago
8 0

Yes, it is known as <u>distillation</u>.

Misha Larkins [42]1 year ago
6 0

The industrial process that utilizes that strategy of evaporation to separate a solution is known as Distillation.

<h3>What is Evaporation?</h3>

Evaporation may be defined as the methodology of liquid transforming into vapors even below its boiling point.

Distillation is an influential technique to isolate mixtures that are constituted of two or more refined liquids.

Distillation is a purification procedure where the elements of a liquid combination are vaporized and then compacted and sequestered.

Therefore, it is well described above.

To learn more about Distillation, refer to the link:

brainly.com/question/24553469

#SPJ1

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If 10.0 mL of a .600 M of HNO3 reacts with 31.0 mL of .700M Ba(OH)2 solution, what is the molarity of Ba(OH)2 after the reaction
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Answer:

<u></u>

  • <u>0.456M</u>

Explanation:

<u>1. Balanced molecular equation</u>

     2HNO_3+Ba(OH)_2\rightarrow Ba(NO_3)_2+2H_2O

<u>2. Mole ratio</u>

     \dfrac{2molHNO_3}{1molBa(OH)_2}

<u>3. Moles of HNO₃</u>

  • Number of moles = Molarity × Volume in liters
  • n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃

<u>4. Moles Ba(OH)₂</u>

  • n = 0.700M × 0.0310 liter = 0.0217 mol

<u>5. Limiting reactant</u>

Actual ratio:

   \dfrac{0.0600molHNO_3}{0.0217molBa(OH)_2}\approx0.28

Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.

Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.

<u>6. Final molarity of Ba(OH)₂</u>

  • Molarity = number of moles / volume in liters
  • Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M
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