Q1. They are highly reactive. Q2. High reactivity, nonmetallic. Q3. Oxygen has an ion charge of -2. Q4. LiCl I believe. Q5. How electrons are shared. Q6 1. Q7. Share 2 valence electrons, I believe.
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
C.) perpendicular
Explanation:
A particle with an electric charge experiences the maximum deflecting force when it is positioned perpendicular to the magnetic field.
Answer:
The answer to your question is E = 83.2 J
Explanation:
Data
Element: Gold
Initial temperature = T1 = 5°C
Final temperature = T2 = 37°C
mass = 20 g
Specific heat = 130 J/kg°K
Process
1.- Convert temperature to kelvin
T1 = 273 + 5 = 278°K
T2 = 273 + 37 = 310°K
2.- Convert mass to kg
1000 g --------------- 1 kg
20 g --------------- x
x = (20 x 1)/1000
x = 0.02 kg
3.- Formula
E = mC(T2 -T1)
4.- Substitution
E = (0.02)(130)(310 - 278)
E = (0.02)(130)(32)
E = 83.2 J