Answer:
(δ+) C → O (δ-)
(δ-) O ← Cl (δ+)
(δ+) O → F (δ-)
(δ+) C → N (δ-)
(δ-) Cl ← C (δ+)
(δ-) S ← H (δ+)
(δ+) S → Cl (δ-)
Explanation:
The polarity of a bond depends on the difference of electronegativity (EN) between the atoms that form it. The dipole moment (μ) points to the atom with the highest electronegativity, which is the one with a negative charge density (δ-), while the other atom has a positive charge density (δ+).
<em>The first bond is between C and O. </em>
EN(C) = 2.5; EN (O) = 3.5
(δ+) C → O (δ-)
<em>The second bond is between O and Cl. </em>
EN(O) = 3.5 ; EN(Cl) = 3.0
(δ-) O ← Cl (δ+)
<em>The third bond is between O and F. </em>
EN(O) = 3.5; EN(F) = 4.0
(δ+) O → F (δ-)
<em>The fourth bond is between C and N. </em>
EN(C) = 2.5; EN(N) = 3.0
(δ+) C → N (δ-)
<em>The fifth bond is between Cl and C. </em>
EN(Cl) = 3.0; EN(C) = 2.5
(δ-) Cl ← C (δ+)
<em>The sixth bond is between S and H. </em>
EN(S) = 2.5; EN(H) = 2.1
(δ-) S ← H (δ+)
<em>The seventh bond is between S and Cl.</em>
EN(S) = 2.5; EN(Cl) = 3.0
(δ+) S → Cl (δ-)
Answer:
1.48 x 10^47 mol of Na
Explanation:
8.90 x 10^24 atoms of Na (1 mol of Na/6.022 x 10^23 atoms of Na)=
1.48 x 10^47 mol of Na
Answer:
。 • ゚ 。 .
. . 。 。
. 。 ඞ 。 . •
゚ you are the Impostor. 。 .
' 0 Impostors remain 。
゚ . . , . .
Explanation:
Answer:
See below
Explanation:
It is neither, at least not at room temperature.
Citric acid exists as a power at room temperature, but can be crystallized from cold water. This can be considered it's " solid state, " but as I mentioned before this acid is a powder. Take a look at the attachment below. This is a citric acid present as a crystal;
Answer:
C. BF3
Explanation:
The boron in BF3 is electron poor and has an empty orbital, so it can accept a pair of electrons, making it a Lewis acid.