All categories

3 years ago

50 points please do this In your OWN WORDS DO NOT COPY FROM SOMEWHERE ELSE!

Chemistry

1 answer:

Roman55 [17]3 years ago

4 0

Answer:

2500 J

Explanation:

Let's solve the problem using the first law of thermodynamics, which states that

U_f - U_i = Q-W

where

Uf is the final internal energy

Ui is the initial internal energy

Q is the heat absorbed by the system

W is the work done by the system

In this problem, we have:

Ui = 2000 J is the initial internal energy

Q = 1000 J is the heat absorbed by the system

W = 500 J is the work done by the piston

If we substitute numbers into the equation, we find:

U_f =U_i + Q-W=2000 J+1000 J-500 J=2500 J

You might be interested in

How is Oxygen -18 different from oxygen -16?

STatiana [176]

Answer:The only one difference is that ozone is made up of three oxygen atoms, while the stuff we breathe is made up of only two atoms.

Explanation:

8 0

3 years ago

What volume of carbon dioxide is produced when 6.40 g of methane gas, CH4 (g), reacts with excess oxygen? All gases are at 35.0C

Mandarinka [93]

Answer:

V = 10.3 L

Explanation:

Given data:

Mass of methane = 6.40 g

Volume of CO₂ produced = ?

Temperature = 35°C (35+273 = 308 K)

Pressure = 100.0 KPa (100.0/101 = 0.98 atm)

Solution:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/molar mass

Number of moles = 6.40 g/ 16 g/mol

Number of moles = 0.4 mol

Now we will compare the moles of CO₂ with CH₄.

CH₄ : CO₂

1 : 1

0.4 : 0.4

Volume of CO₂:

Formula:

PV = nRT

0.98 atm ×V = 0.4 mol ×0.0821 atm.L/mol.K × 308 K

0.98 atm ×V = 10.11 atm.L

V = 10.11 atm.L /0.98 atm

V = 10.3 L

3 0

2 years ago

The type of chemical reaction represented by the following equation is...

Jet001 [13]

Answer:

i believe the answer is a

Explanation:

5 0

2 years ago

Read 2 more answers

Someone please help me real quick pls :(

Genrish500 [490]

Anti-acids because they contain Alkaline ion that chemically neutralizes stomach acid

8 0

2 years ago

Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M

liberstina [14]

Answer:

$= \mathbf{C_3H_6O}$

Explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

So, by applying the 13th rule;

we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r = no. of hydrogen.

So;

$\dfrac{58}{13}= 4 \ remainder \ 6$

So;

$C_nH_{n+r} = C_4H_{4+6}$

$= C_4H_{10}$

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing $CH_4$ . Also, since the mass is an even number then Nitrogen is 0.

So, we have:

$= \mathbf{C_3H_6O}$

6 0

2 years ago