The celery and carrot will most likely become saltier and perhaps more shriveled because of the high concentration of salt in the water solution compared to the low concentration of salt in the solution. The raisin, however, could take two roots, one would be the same as the carrot and celery, but the other one is it would soak up water because of how salty and shriveled the raisin already is.

7 0

3 years ago

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In this prelab exercise, you will calculate how to prepare solutions that you will make in lab. Below is an example of how to pr

Anastasy [175]

Explanation:

$Molarity=\frac{\text{Moles of compound}}{\text{Volume of solution (L)}}$

Moles of compound =

$\frac{\text{mass of compound}}{\text{Molar mass of compound}}$

We have ;

Volume of solution = 600 mL = 0.600 L ( 1 mL = 0.001 L)

Moles of NaOH = n

Molarity of the solution = 3 M

$3M=\frac{n}{0.600 L}$

n = 3 M × 0.600 L = 1.800 mol

Mass of 1.800 mole sof NaOH :

1.800 mol × 40 g/mol = 72.0 g

Preparation:

Weight 72.0 grams of sodium hydroxide and add it to the 500 mL of volumetric flask along with some water. Dissolve the all the solute by adding small proportion of water. After the solution becomes clear make the water upto the mark of 500 ml.

Transfer the solution to a bigger beaker and 100 mL of water more to it.

6 0

3 years ago

What mass of salt (nacl) should you add to 1.48 l of water in an ice cream maker to make a solution that freezes at -13.4 ∘c ? a

blagie [28]

Answer is: mass of salt is 311,15 g.
V(H₂O) = 1,48 l · 1000 ml/l = 1480 ml.
m(H₂O) = 1480 g = 1,48 kg.
d(solution) = 1,00 g/ml.
ΔT(solution) = 13,4°C = 13,4 K.
Kf = 1,86 K·kg/mol; cryoscopic constant of water
i(NaCl) = 2; Van 't Hoff factor.
ΔT(solution) = Kf · b · i.
b(NaCl) = 13,4 K ÷ (1,86 K·kg/mol · 2).
b(NaCl) = 3,6 mol/kg.
n(NaCl) = 3,6 mol · 1,48 kg= 5,328 mol.
m(NaCl) = 5,328 mol · 58,4 g/mol = 311,15 g.

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3 years ago

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