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2 years ago

Describe the difference between a chemical reaction and a physical change.

1 answer:

5 0

A chemical change results from a chemical reaction, while a physical change is when matter changes forms but not chemical identity.

Examples of chemical changes are burning, cooking, rusting, and rotting.

Examples of physical changes are boiling, melting, freezing, and shredding.

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Calculate the slope of each line using the points given. (25.6cm³ , 28.16g), (17.3cm³, 19.03g)

fiasKO [112]

Answer:

1.1

Explanation:

The slope of a line can be calculated using the values of the x and y corrdinates. The equation is given as;

M = ΔY / ΔX = Y2 - Y1 / X2 - X1

From the points;

(25.6cm³ , 28.16g) - (X1, Y1)

(17.3cm³, 19.03g) - (X2, Y2)

Inserting the values into the equation;

M = 19.03 - 28.16 / 17.3 - 25.6

M = -9.13 / -8.3 = 1.1

3 0

2 years ago

16. These conditions occur over the course of a day. Cumulus clouds appear and create rain showers. The sky clears soon after th

olya-2409 [2.1K]

Answer:

Explanation:

I believe it's A gggggg%gggggtggg

6 0

2 years ago

Carbon dioxide gas is collected at 27.0(degrees)C in an evacuated flask with a measured volume of 30.0L. When all the gas has be

White raven [17]

Answer:

Moles of carbon dioxide gas is 0.584 moles.

Mass of 0.584 moles of carbon dioxide gas is 25.7 g

Explanation:

Using ideal gas equation

PV = nRT

where,

P = Pressure of gas = $0.480 atm$

V = Volume of gas = 30.0 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 27°C = 300.15 K

Putting values in above equation, we get:

$(0.480 atm)\times 30.0 L=n\times (0.0821L.atm/mol.K)\times 300.15K\\\\n=0.5844 mol\approx 0.584$

Moles of carbon dioxide gas = 0.584 moles

Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7 g

5 0

2 years ago

Suppose the formation of nitryl fluoride proceeds by the following mechanism: step elementary reaction rate constant (g) (g) (g)

ziro4ka [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$2NO_2 _{(g)} + F_2_{(g)} ----> 2NO_2 F_{(g)}$

$r = \frac{ k [NO_2]^2 [F_2]}{[NO_2F]}$

Explanation:

From the question we are told that

The formation mechanism is

$NO_2_{(g)} + F_2 _{(g)} ----> NO_2 F_{(g)} + F_{(g)}$

$F_{(g)} + NO_2 _{(g)} ---> NO_2 F_{(g)}$

The overall balanced equation is

$2NO_2 _{(g)} + F_2_{(g)} ----> 2NO_2 F_{(g)}$

We combined the first reactant and the last product and the balanced the number of mole

The observable rate law is

$r = \frac{ k [NO_2]^2 [F_2]}{[NO_2F]}$

This rate law is derived from the balanced chemical equation

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2 years ago

The earth's atmosphere is composed of 78% nitrogen, 21% oxygen, 0.9% argon, and 0.1% traces of other gases. If the total pressur

damaskus [11]

Answer:

xnbdnxndxnzxxndsns dnx dnx d nndfdrrr

Explanation:

ndnndndjdjwwoqowwddvxbdsaajejrgxxbc

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3 years ago