The reaction yields the product compound 2,4,5-tribromophenol.
<h3>Bromination of monohydroxy benzene</h3>
Bromination is an organic reaction in which aqueous bromine is made to react with another compound so as to introduce bromine into the molecule.
When we carry out the bromination of monohydroxy benzene, we obtain the compound 2,4,5-tribromophenol.
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Distance = 556 km
Time = 3.4 h
Speed = Distance / Time = 556 / 3.4 = 163.52 km/h
Answer:
<em>a)</em> <em>1.392 x 10^6 g/cm^3</em>
<em>b) 8.69 x 10^7 lb/ft^3</em>
<em></em>
Explanation:
mass of the star m = 2.0 x 10^36 kg
radius of the star (assumed to be spherical) r = 7.0 x 10^5 km = 7.0 x 10^8 m
The density of substance ρ = mass/volume
The volume of the star = volume of a sphere = 
==> V =
= 1.437 x 10^27 m^3
density of the star ρ = (2.0 x 10^36)/(1.437 x 10^27) = 1.392 x 10^9 kg/m^3
in g/cm^3 = (1.392 x 10^9)/1000 = <em>1.392 x 10^6 g/cm^3</em>
in lb/ft^3 = (1.392 x 10^9)/16.018 = <em>8.69 x 10^7 lb/ft^3</em>
Empirical formula of the Cyclopropane = C
Molecular formula of the Cyclopropane = 
Cyclopropane is a cyclic compound having 3 carbon atoms in a ring.
As we know carbon is having 4 valency, that means it can form 4 bonds with other atoms.
In case of cyclopropane each carbon atom is attached with 2 carbon atoms in a ring, so 2 valency of each carbon atom is used in a ring formation.
The remaining 2 valency are satisfied by hydrogen atoms.
Here, 3 carbons are there so 6 hydrogens are used to satisfy their valency.
An empirical formula is a simple representation of ratio of the atoms present, while a molecular formula is a detailed representation of the total number of atom.
So here, carbon and hydrogen ratio is 1:2 , from this the Empirical formula of the Cyclopropane became C
And the molecular formula of the Cyclopropane is
.
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