Answer:
16,18,22
Or
1,3,7
Explanation:
The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation
A car moving due east increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s. How far, in meters, did the car travel whil
1 answer:
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Answer:
a) speed when Jack sees the pot : 12.92 meters per second
b) height difference 163.115 meters
Explanation:
First to calculate te initial speed we use the acceleration formula:
a= v1-v0/t
Acceleration being gravity's acceleration (9.8 m/s^2)
v1 being the speed when Jill sees the pot
v0 when Jack sees it
and t the time between
Solving for v0 it would be
v1 - a*t = v0
replacing
For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)
The formula is
replacing
a) The work done is 920 J
b) The work done is 5200 J
Explanation:
a)
In this first part of the problem, the crate is moved horizontally at constant speed.
The work required in this case is given by
where
F is the magnitude of the force applied
d is the displacement of the crate
is the angle between the direction of the force and of the displacement
Here the crate is moved at constant speed: this means that the acceleration of the crate is zero, and so according to Newton's second law, the net force on the crate is zero: this means that the force applied, F, must be equal to the force of friction (but in opposite direction), so
F = 230 N
The displacement is
d = 4.0 m
And the angle is , since the force is applied horizontally. Therefore, the work done is
b)
In this case, the crate is moved vertically. The force that must be applied to lift the crate must be equal to the weight of the crate (in order to move it a constant speed), therefore
F = W = 1300 N
The displacement this time is again
d = 4.0 m
And the angle is , since the force is applied vertically, and the crate is moved also vertically. Therefore, the work done on the crate this time is
Learn more about work:
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