Ionic bond.
In the ionic bond one atom loses one or more electrons, leaving the atom with positive charge, and the other atom accepts those electrons standing with negative charge.
Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
Answer:
<h3>1.03684m</h3>
Explanation:
Using the formula for calculating range expressed as;
R = U√2H/g where
R is the distance moves in horizontal direction = 18.4m
H is the height
U is the velocity of the baseball = 40m/s
g is the acceleration due to gravity = 9.8m/s²
Substitute the given parameters into the formula and calculate H as shown;
18.4 = 40√2H/9.8
18.4/40 = √2H/9.8
0.46 = √2H/9.8
square both sides;
(0.46)² = (√2H/9.8)²
0.2116 = 2H/9.8
2H = 9.8*0.2116
2H = 2.07368
H = 2.07368/2
H = 1.03684m
Hence the ball is 1.03684m below the launch height when it reached home plate.
<h2>
Option C is the correct answer.</h2>
Explanation:
Specific gravity of fluid = 0.750
Density of fluid = Specific gravity of fluid x Density of water
Density of fluid = 0.750 x 1000
Density of fluid = 750 kg/m³
Mass of fluid = 22.5 kg
We have
Mass = Volume x Density
22.5 = Volume x 750
Volume = 0.03 m³ = 30 L
Option C is the correct answer.
C. The higher the altitude the less gravity affects you