The problem involves the conversion of potential energy to kinetic energy as the object falls from rest. Energy is conserved, so the equation used is:
PEi + KEi = PEf + KEf
Since the object is falling from rest, the initial kinetic energy is zero. Also, since the object hits the ground at its final position, the final potential energy is zero. This leaves:
PEi = KEf mgh = 1/2 mv^2
*cancel out mass on both sides of the equation
gh = 0.5v^2 v = sqrt(2gh) = sqrt(2*9.81*4.5) = 9.40 m/s --> final ans.
