What happens to light when it passes through a lens?

2 answers:

7 0

B. Light refracts as it passes through a lens.

The bending of a ray of light also occurs when light passes into and out of a glass lens. ... Because a convex lens can cause rays of light to converge, it can produce an image on a screen.

Art [367]3 years ago

5 0

Answer:B the light refracts.

Explanation: a good example is an straw in a cup. When the light goes through the glass the straw looks broken an bigger

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If an amount of heat Q is needed to increase the temperature of a solid metal sphere of diameter D from 4°C to 7°C, the amount o

Hitman42 [59]

Answer:

Q = c M ΔT where c is the heat capacity and M the mass present

Q2 / Q1 = M2 / M1 since the other factors are the same

M = ρ V where ρ is the density

M = ρ Π (d / 2)^2 where d is the diameter of the sphere

M2 / M1 = (2 D/2)^2 / (D/2)^2 = 4

It will take 4Q heat to heat the second sphere

7 0

2 years ago

A 17.0 resistor and a 6.0 resistor are connected in series with a battery. The potential difference across the 6.0 resistor is m

tia_tia [17]

Answer:

V= 57.5 V

Explanation:

If the resistors are in the linear zone of operation, the potential difference across them, must obey Ohm's law:

$V = I*R$

For the 6.0 Ω resistor, if the potential difference across it is 15 V, we can find the current flowing through it as follows:

$I = \frac{V}{R} = \frac{15 V}{6.0 \Omega} = 2.5 A$

In a series circuit, the current is the same at any point of it, so the current through the battery is I = 2.5 A
The equivalent resistance of a series circuit is just the sum of the resistances, so, in this case, we can write the following equation:

$R_{eq} = R_{1} +R_{2} = 17.0 \Omega + 6.0 \Omega = 23.0 \Omega$

Applying Ohm's Law to the equivalent resistance, we can find the potential difference through it, that must be equal to the potential difference across the battery, as follows:

$V = I* R_{eq} = 2.5 A * 23.0 \Omega = 57.5 V$

8 0

2 years ago

Convert horsepower to Kilo Newton.

SVEN [57.7K]

1 horsepower is equivalent to 0.7457 Kilo Newton. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0

3 years ago

A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.

ValentinkaMS [17]

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

$v = 1.74 x 10^{3} ( \frac{m}{s} )$