<span>Answer:
A 0.04403 g sample of gas occupies 10.0-mL at 289.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl. What is the molecular formula of the compound?
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Seems like I did a problem very similar to this--this must be the "B" test. But the halogen was different.
25.305% C/12 = 2.108
74.695% Cl/35.5 = 2.104
So the empirical formula would be CH. However, there are many compounds which fit this bill, so we have to use the gas data. (And I made, in the previous problem, the simplifying assumption that 289C and 1.10 atm would offset each other, so I'll do that, too.)
0.044 grams/10 ml = x/22.4 liters
0.044g/0.010 liters = x/22.4 liters
22.4 liters/0.010 liters = 2240 (ratio)
2240 x .044 = 98.56 (actual atomic weight)
CCl = 35.5+12 or 47.5, so two of those is 95 grams/mole.
This is sufficiient to distinguish C2CL2, (dichloroacetylene)
from C6CL6 (hexachlorobenzene) which would
mass 3 times as much.</span>
A cellphone battery is a electrical energy
and a piston in an engine is an thermal energy
I am pretty sure it is 4.002602
Answer:
B. Household ammonia.
Explanation:
NH₃ is a base, so the solution always will be basic.
NH₃ takes the proton from the water. In conclusion we have free OH⁻ in medium, that's why the solution is basic.
NH₃ + H₂O → NH₄⁺ + OH⁻
- HCl + H₂O → H₃O⁺ + Cl⁻
This reaction makes an acid solution, cause the H₃O⁺
- Vinegar is a compound made of acetic acid.
CH₃COOH + H₂O ⇄ H₃O⁺ + CH₃COO⁻
This reaction also makes an acid solution, cause the H₃O⁺
- Pure water makes neutral solution. It is not acid, neither basic.
2H₂O ⇄ H₃O⁺ + OH⁻
