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Veseljchak [2.6K]
3 years ago
14

What is the relative rate of effusion for hydrogen iodide (128 g/mol) compared to gaseous hydrochloric acid (36.5 g/mol)

Chemistry
1 answer:
MArishka [77]3 years ago
8 0

This question is hard but I found the answer from merit nation

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Calculate the number of neutrons in potassium-40.
dsp73

Answer:

21 neutrons

Explanation:

There are 21 neutrons in Pottasium-40

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Adding sugar to your tea physical or chemical change ​
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Answer:

physical

Explanation:

no chemical reaction occurs

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Which element is non-metallic and a gas at room temperature?
ANEK [815]

Answer:

Notrogen(N)

Explanation:

Plz mark me as brilliant

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2 years ago
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40o+2 protons electrons And neurons
KatRina [158]

Answer: There are few simple rules to follow.

(1) The atomic number is equal to the number of protons.

Z

= number of protons

(2) In neutrally charged elements, the number of electrons is the same as the number of protons.  

Z

= number of protons = number of electrons (no charge)

Otherwise, positive charge means that the element lost an electron and negative charge means it gained an electron.

(3) The atomic mass is equal to the sum of the number of protons and number of neutrons.

A

= number of protons + number neutrons  

or

A

=  

Z

+ number neutrons

So if you say that  

Z

= 20 and  

A

= 40, then

A

=  

Z

+ number neutrons

40 = 20 + number of neutrons

40 - 20 = number of neutrons

Therefore,

number of neutrons = 20

Explanation:

7 0
3 years ago
A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?
REY [17]

Answer:

Sn_2O

Explanation:

Hello,

In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:

\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%

Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:

n_{Sn}=93.6gSn*\frac{1molSn}{118.8gSn} =0.788molSn\\\\n_O=6.4gO*\frac{1molO}{16gO}=0.4molO

In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:

Sn:\frac{0.788}{0.4}=2\\ \\O:\frac{0.4}{0.4}=1

Therefore, the empirical formula is:

Sn_2O

Best regards.

8 0
3 years ago
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